CDS · NDA · AFCAT · Indian Army / Navy / Air Force Exams
ax² + bx + c = 0
x = [-b ± √(b²-4ac)] / 2a
Sum of roots = −b/a; Product of roots = c/a. Nature of roots questions appear every year. Memorise the relationship between coefficients and roots.
nth term: aₙ = a + (n-1)d
Sum: Sₙ = n/2 [2a + (n-1)d]
nth term: aₙ = arⁿ⁻¹
Sum (finite): Sₙ = a(rⁿ-1)/(r-1), r≠1
Sum (infinite, |r|<1): S∞ = a/(1-r)
(x + y)ⁿ = Σ ⁿCᵣ · xⁿ⁻ʳ · yʳ (r = 0 to n)
General term: T(r+1) = ⁿCᵣ · xⁿ⁻ʳ · yʳ
For NDA, focus on finding the middle term and coefficient of a specific term. The sum of coefficients is obtained by putting x = y = 1: sum = 2ⁿ.
| Angle | sin | cos | tan |
|---|---|---|---|
| 0° | 0 | 1 | 0 |
| 30° | 1/2 | √3/2 | 1/√3 |
| 45° | 1/√2 | 1/√2 | 1 |
| 60° | √3/2 | 1/2 | √3 |
| 90° | 1 | 0 | ∞ |
sin²θ + cos²θ = 1
1 + tan²θ = sec²θ
1 + cot²θ = cosec²θ
sin(A±B) = sinA·cosB ± cosA·sinB
cos(A±B) = cosA·cosB ∓ sinA·sinB
tan(A±B) = (tanA ± tanB)/(1 ∓ tanA·tanB)
sin2A = 2sinA·cosA
cos2A = cos²A - sin²A = 1 - 2sin²A = 2cos²A - 1
tan2A = 2tanA/(1 - tan²A)
| Type | Property |
|---|---|
| Row Matrix | 1 × n (single row) |
| Column Matrix | m × 1 (single column) |
| Square Matrix | m = n |
| Diagonal Matrix | Non-diagonal elements = 0 |
| Identity Matrix (I) | Diagonal = 1, rest = 0; A·I = A |
| Symmetric Matrix | A = Aᵀ (transpose = original) |
| Skew-Symmetric | A = −Aᵀ; diagonal elements = 0 |
|A| = ad - bc for [[a,b],[c,d]]
A⁻¹ exists only if |A| ≠ 0 (non-singular matrix).
A⁻¹ = adj(A) / |A|, where adj(A) is the adjugate (transpose of cofactor matrix).
| Function | Derivative |
|---|---|
| xⁿ | nxⁿ⁻¹ |
| eˣ | eˣ |
| ln x | 1/x |
| sin x | cos x |
| cos x | −sin x |
| tan x | sec²x |
Chain: d/dx[f(g(x))] = f'(g(x))·g'(x)
Product: d/dx[uv] = u'v + uv'
Quotient: d/dx[u/v] = (u'v - uv')/v²
f'(x) = 0 at critical points. If f''(x) < 0 → local maximum. If f''(x) > 0 → local minimum. Rate of change, increasing/decreasing functions tested in NDA.
| Function | Integral |
|---|---|
| xⁿ | xⁿ⁺¹/(n+1) + C, n≠−1 |
| 1/x | ln|x| + C |
| eˣ | eˣ + C |
| sin x | −cos x + C |
| cos x | sin x + C |
| sec²x | tan x + C |
∫[a to b] f(x)dx = F(b) − F(a)
Area under a curve between x = a and x = b.
| Formula | Expression |
|---|---|
| Distance PQ | √[(x₂−x₁)² + (y₂−y₁)²] |
| Mid-point | ((x₁+x₂)/2, (y₁+y₂)/2) |
| Slope (m) | (y₂−y₁)/(x₂−x₁) |
| Slope-intercept form | y = mx + c |
| Point-slope form | y − y₁ = m(x − x₁) |
| Two-point form | (y−y₁)/(y₂−y₁) = (x−x₁)/(x₂−x₁) |
Centre (0,0): x² + y² = r²
Centre (h,k): (x−h)² + (y−k)² = r²
General: x² + y² + 2gx + 2fy + c = 0 → centre (−g,−f), r = √(g²+f²−c)
| Conic | Standard Equation | Key Property |
|---|---|---|
| Parabola | y² = 4ax | Focus (a,0); Directrix x = −a |
| Ellipse | x²/a² + y²/b² = 1 (a>b) | Foci (±c,0); c² = a²−b² |
| Hyperbola | x²/a² − y²/b² = 1 | Foci (±c,0); c² = a²+b² |
| Measure | Definition | Formula |
|---|---|---|
| Mean (x̄) | Sum ÷ Count | Σxᵢ/n |
| Median | Middle value (sorted) | For even n: avg of n/2 and (n/2+1) |
| Mode | Most frequent value | — |
Range = Maximum − Minimum
Variance (σ²) = Σ(xᵢ − x̄)²/n
Standard Deviation (σ) = √Variance
P(E) = Favourable outcomes / Total outcomes
0 ≤ P(E) ≤ 1; P(E) + P(E') = 1
P(A∪B) = P(A) + P(B) − P(A∩B)
P(A∩B) = P(A)·P(B) if A and B are independent
P(A|B) = P(A∩B) / P(B)
Bayes' theorem questions and problems on balls-in-urns are common. Practice systematically listing sample spaces.
| Shape | Area / Volume | Perimeter / Surface Area |
|---|---|---|
| Circle | πr² | 2πr |
| Triangle | ½ × b × h (or Heron's) | a+b+c |
| Rectangle | l × b | 2(l+b) |
| Cube | a³ | 6a² |
| Cylinder | πr²h | 2πr(r+h) |
| Cone | ⅓πr²h | πr(r+l), l=√(r²+h²) |
| Sphere | 4/3 πr³ | 4πr² |
| Divisor | Rule |
|---|---|
| 2 | Last digit even |
| 3 | Sum of digits divisible by 3 |
| 4 | Last two digits divisible by 4 |
| 5 | Ends in 0 or 5 |
| 9 | Sum of digits divisible by 9 |
| 11 | (Sum of odd-position digits) − (Sum of even-position digits) divisible by 11 |
HCF × LCM = Product of two numbers
For CDS: ratio problems, time & work, speed & distance often reduce to HCF/LCM. Practice identifying the right approach quickly.