1. Chapter at a Glance
Algebra and Trigonometry together give roughly 45–55 of the 120 questions in NDA Paper I, and the same ideas appear in a simpler form in CDS Elementary Mathematics and AFCAT Numerical Ability. The level is Class XI–XII (NCERT). Most questions are direct applications of a standard result, so the winning strategy is to know every formula cold and recognise the pattern in 10–15 seconds. This chapter covers sets and relations, complex numbers, quadratic equations, sequences and series, permutations and combinations, the binomial theorem, logarithms, matrices and determinants, and trigonometry including heights and distances.
- Read each section, then cover the master formula table and try to write every formula from memory.
- Solve the PYQ-based questions at the end without looking at the solutions; then compare your method with the shortcut given.
- NDA has a one-third negative mark (−0.83 for a 2.5-mark question). Attempt a question if you can eliminate two options with confidence.
- Time budget in NDA: 150 minutes for 120 questions — about 75 seconds per question. Algebra and trigonometry should be your fast-scoring zone.
2. Sets, Relations and Functions
A set is a well-defined collection of objects. Key results:
- A set with n elements has 2ⁿ subsets and 2ⁿ − 1 proper subsets.
- n(A ∪ B) = n(A) + n(B) − n(A ∩ B); for three sets, n(A ∪ B ∪ C) = n(A) + n(B) + n(C) − n(A∩B) − n(B∩C) − n(C∩A) + n(A∩B∩C).
- De Morgan's laws: (A ∪ B)′ = A′ ∩ B′ and (A ∩ B)′ = A′ ∪ B′.
- If n(A) = m and n(B) = n, the number of relations from A to B is 2^(mn); the number of functions from A to B is nᵐ.
- A relation is an equivalence relation if it is reflexive, symmetric and transitive.
- A function is one-one (injective) if different inputs give different outputs, onto (surjective) if every element of the codomain is an image, and bijective if both. Only bijections have inverses.
Number of one-one functions from a set of m elements to a set of n elements (m ≤ n) = ⁿPₘ = n!/(n − m)!. If m = n, it is simply n!.
3. Complex Numbers
A complex number is z = a + ib, where i² = −1. Its modulus is |z| = √(a² + b²) and its conjugate is z̄ = a − ib. In polar form, z = r(cos θ + i sin θ), where r = |z| and θ = arg z.
- Powers of i repeat in a cycle of 4: i, −1, −i, 1. So iⁿ depends only on the remainder when n is divided by 4. Example: i¹⁰³ = i³ = −i.
- z·z̄ = |z|²; |z₁z₂| = |z₁||z₂|; arg(z₁z₂) = arg z₁ + arg z₂.
- Cube roots of unity: 1, ω, ω², where ω = (−1 + i√3)/2. Key facts: 1 + ω + ω² = 0 and ω³ = 1.
- De Moivre's theorem: (cos θ + i sin θ)ⁿ = cos nθ + i sin nθ.
- |z − z₀| = r represents a circle with centre z₀ and radius r.
Students often write √(−4) × √(−9) = √36 = 6. This is wrong: √(−4) × √(−9) = 2i × 3i = 6i² = −6. The rule √a·√b = √(ab) holds only when a and b are not both negative.
4. Quadratic Equations
For ax² + bx + c = 0 (a ≠ 0), the roots are x = [−b ± √(b² − 4ac)]/2a. The discriminant D = b² − 4ac decides the nature of roots:
| Discriminant | Nature of roots | Example |
|---|---|---|
| D > 0, perfect square (a, b, c rational) | Real, distinct, rational | x² − 5x + 6 = 0 → 2, 3 |
| D > 0, not a perfect square | Real, distinct, irrational (conjugate pair) | x² − 2x − 1 = 0 → 1 ± √2 |
| D = 0 | Real and equal | x² − 4x + 4 = 0 → 2, 2 |
| D < 0 | Non-real complex conjugates | x² + x + 1 = 0 → ω, ω² |
- Sum of roots α + β = −b/a; product αβ = c/a.
- The equation with roots α, β is x² − (α + β)x + αβ = 0.
- α² + β² = (α + β)² − 2αβ; (α − β)² = (α + β)² − 4αβ; α³ + β³ = (α + β)³ − 3αβ(α + β).
- If one root is the reciprocal of the other, then c = a. If roots are equal in magnitude and opposite in sign, then b = 0.
- For a cubic ax³ + bx² + cx + d = 0: sum of roots = −b/a, sum of products taken two at a time = c/a, product = −d/a.
5. Sequences and Series
| Progression | nth term | Sum of n terms | Mean of two numbers a, b |
|---|---|---|---|
| Arithmetic (AP) | a + (n − 1)d | n/2 [2a + (n − 1)d] = n/2 (first + last) | AM = (a + b)/2 |
| Geometric (GP) | arⁿ⁻¹ | a(rⁿ − 1)/(r − 1), r ≠ 1; infinite sum a/(1 − r) for |r| < 1 | GM = √(ab) |
| Harmonic (HP) | reciprocal of the AP term | no simple formula | HM = 2ab/(a + b) |
- For two positive numbers, AM ≥ GM ≥ HM, and GM² = AM × HM.
- Σn = n(n + 1)/2; Σn² = n(n + 1)(2n + 1)/6; Σn³ = [n(n + 1)/2]².
- If three numbers are in AP, take them as a − d, a, a + d; in GP, as a/r, a, ar. This makes the algebra short.
6. Permutations, Combinations and Binomial Theorem
Fundamental principle: if one job can be done in m ways and another in n ways, both together can be done in m × n ways (and either one in m + n ways when they cannot happen together).
- ⁿPᵣ = n!/(n − r)! (arrangements, order matters); ⁿCᵣ = n!/[r!(n − r)!] (selections, order does not matter).
- ⁿCᵣ = ⁿCₙ₋ᵣ; ⁿCᵣ + ⁿCᵣ₋₁ = ⁿ⁺¹Cᵣ; sum of all ⁿCᵣ = 2ⁿ.
- Arrangements of n things with p alike of one kind and q alike of another = n!/(p! q!). Example: letters of "ARMY" = 4! = 24; "NAVY" = 4! = 24; "INDIA" = 5!/2! = 60.
- Circular arrangements of n distinct objects = (n − 1)!; for a necklace or garland (clockwise = anticlockwise) = (n − 1)!/2.
- Number of diagonals of an n-sided polygon = ⁿC₂ − n = n(n − 3)/2.
Binomial theorem: (x + y)ⁿ = Σ ⁿCᵣ xⁿ⁻ʳ yʳ, r = 0 to n. The general term is T(r+1) = ⁿCᵣ xⁿ⁻ʳ yʳ. There are n + 1 terms. If n is even, the middle term is T(n/2 + 1); if n is odd, there are two middle terms.
In (xᵃ + 1/xᵇ)ⁿ, write the power of x in the general term, set it equal to zero and solve for r. For (x + 1/x)⁶: power of x in T(r+1) = 6 − 2r = 0 ⇒ r = 3, term = ⁶C₃ = 20.
7. Logarithms and Exponents
- log(mn) = log m + log n; log(m/n) = log m − log n; log mⁿ = n log m.
- Change of base: logₐ b = log b / log a; logₐ b × log_b a = 1; logₐ 1 = 0; logₐ a = 1.
- a^(logₐ x) = x. log₁₀ 2 ≈ 0.3010, log₁₀ 3 ≈ 0.4771 (useful to count digits: number of digits in 2³⁰ = ⌊30 × 0.3010⌋ + 1 = 10).
8. Matrices and Determinants
A matrix of order m × n has m rows and n columns. Two matrices can be multiplied only if the number of columns of the first equals the number of rows of the second; matrix multiplication is not commutative in general (AB ≠ BA).
- Transpose: (AB)ᵀ = BᵀAᵀ. A is symmetric if Aᵀ = A, skew-symmetric if Aᵀ = −A (diagonal elements of a skew-symmetric matrix are zero).
- For a 2 × 2 matrix [[a, b], [c, d]], determinant = ad − bc and inverse = (1/(ad − bc)) [[d, −b], [−c, a]].
- A⁻¹ exists only if |A| ≠ 0 (non-singular). A⁻¹ = adj A / |A|.
- For a square matrix of order n: |kA| = kⁿ|A|; |adj A| = |A|ⁿ⁻¹; |AB| = |A||B|; |Aᵀ| = |A|; |A⁻¹| = 1/|A|.
- Properties of determinants: interchanging two rows changes the sign; two identical rows make the determinant zero; adding a multiple of one row to another does not change it.
- Area of a triangle with vertices (x₁, y₁), (x₂, y₂), (x₃, y₃) = ½ |x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)|. Area zero ⇒ points are collinear.
- Cramer's rule (system AX = B): if |A| ≠ 0, a unique solution exists; if |A| = 0 and (adj A)B ≠ 0, no solution; if |A| = 0 and (adj A)B = 0, infinitely many or none.
9. Trigonometry
Angles are measured in degrees or radians: π radians = 180°, so 1 radian ≈ 57.3°. Length of an arc s = rθ (θ in radians).
| Angle | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
| sin | 0 | 1/2 | 1/√2 | √3/2 | 1 |
| cos | 1 | √3/2 | 1/√2 | 1/2 | 0 |
| tan | 0 | 1/√3 | 1 | √3 | not defined |
- Identities: sin²θ + cos²θ = 1; 1 + tan²θ = sec²θ; 1 + cot²θ = cosec²θ.
- ASTC rule ("All Silver Tea Cups"): in quadrant I all ratios are positive, in II only sin (and cosec), in III only tan (and cot), in IV only cos (and sec).
- Compound angles: sin(A ± B) = sin A cos B ± cos A sin B; cos(A ± B) = cos A cos B ∓ sin A sin B; tan(A + B) = (tan A + tan B)/(1 − tan A tan B).
- Double angles: sin 2A = 2 sin A cos A; cos 2A = cos²A − sin²A = 1 − 2 sin²A = 2 cos²A − 1; tan 2A = 2 tan A/(1 − tan²A).
- Triple angles: sin 3A = 3 sin A − 4 sin³A; cos 3A = 4 cos³A − 3 cos A.
- Maximum value of a sin θ + b cos θ is √(a² + b²) and minimum is −√(a² + b²).
- In any triangle: sine rule a/sin A = b/sin B = c/sin C = 2R; cosine rule a² = b² + c² − 2bc cos A.
- Principal values of inverse functions: sin⁻¹x ∈ [−π/2, π/2], cos⁻¹x ∈ [0, π], tan⁻¹x ∈ (−π/2, π/2); sin⁻¹x + cos⁻¹x = π/2.
- Angle of elevation is measured upward from the horizontal; angle of depression is measured downward from the horizontal. The angle of elevation of A from B equals the angle of depression of B from A.
- If the angle of elevation changes from α to β as an observer walks a distance d towards a tower, height h = d tan α tan β / (tan β − tan α).
- When the sun's elevation is 45°, the shadow equals the height; at 60°, shadow = h/√3; at 30°, shadow = h√3.
10. Trigonometric Equations and Multiple-Angle Identities
An identity is true for every angle, but an equation is true only for some angles. NDA papers often ask for all solutions of an equation, or for the number of solutions in a given interval. Because trigonometric functions repeat, an equation usually has infinitely many solutions, written as a general solution with an integer n.
| Equation | General solution (n ∈ Z) | Example |
|---|---|---|
| sin θ = 0 | θ = nπ | θ = 0, π, 2π, … |
| cos θ = 0 | θ = (2n + 1)π/2 | θ = π/2, 3π/2, … |
| tan θ = 0 | θ = nπ | same zeros as sin θ |
| sin θ = sin α | θ = nπ + (−1)ⁿα | sin θ = 1/2 ⇒ θ = nπ + (−1)ⁿπ/6 |
| cos θ = cos α | θ = 2nπ ± α | cos θ = 1/2 ⇒ θ = 2nπ ± π/3 |
| tan θ = tan α | θ = nπ + α | tan θ = 1 ⇒ θ = nπ + π/4 |
| sin²θ = sin²α (also cos², tan²) | θ = nπ ± α | tan²θ = 3 ⇒ θ = nπ ± π/3 |
- sin 2A = 2 sin A cos A = 2 tan A/(1 + tan²A); cos 2A = cos²A − sin²A = 1 − 2 sin²A = 2 cos²A − 1.
- tan 2A = 2 tan A/(1 − tan²A); sin 3A = 3 sin A − 4 sin³A; cos 3A = 4 cos³A − 3 cos A.
- sin C + sin D = 2 sin((C + D)/2) cos((C − D)/2); cos C + cos D = 2 cos((C + D)/2) cos((C − D)/2).
- 2 sin A cos B = sin(A + B) + sin(A − B); 2 cos A cos B = cos(A + B) + cos(A − B).
- Maximum of a sin θ + b cos θ is √(a² + b²) and the minimum is −√(a² + b²).
Worked example 1. Solve 2 sin²θ − 3 sin θ + 1 = 0 for 0 ≤ θ ≤ 2π. Treat it as a quadratic in sin θ: (2 sin θ − 1)(sin θ − 1) = 0, so sin θ = 1/2 or sin θ = 1. This gives θ = π/6, 5π/6 and π/2 — three solutions in the interval.
Worked example 2. Find the value of cos 20° cos 40° cos 80°. Multiply and divide by 2 sin 20° and use 2 sin x cos x = sin 2x three times: the product becomes sin 160°/(8 sin 20°) = sin 20°/(8 sin 20°) = 1/8. The pattern cos x cos 2x cos 4x = sin 8x/(8 sin x) appears often in NDA papers.
Worked example 3. Solve sin θ + cos θ = 1 for 0 ≤ θ < 2π. Write the left side as √2 sin(θ + π/4) = 1, so sin(θ + π/4) = 1/√2. Then θ + π/4 = π/4 or 3π/4 (within the shifted range), which gives θ = 0 or θ = π/2. Squaring both sides instead gives 2 sin θ cos θ = 0, whose solutions 0, π/2, π and 3π/2 must be checked: only 0 and π/2 satisfy the original equation, which shows why substitution back is essential.
Worked example 4. If tan A = 1/2 and tan B = 1/3, find A + B for acute angles. tan(A + B) = (1/2 + 1/3)/(1 − 1/6) = (5/6)/(5/6) = 1, so A + B = π/4. This result is a favourite in NDA papers.
- Never divide both sides by sin θ or cos θ without checking whether it can be zero — you may lose solutions.
- Squaring both sides can add false solutions; always substitute back.
- Count solutions only inside the given interval; the general solution gives infinitely many.
11. Master Formula Table
| Topic | Formula / result | Memory hook |
|---|---|---|
| Subsets | 2ⁿ subsets; relations A→B = 2^(mn); functions A→B = nᵐ | "Each element chooses" |
| Powers of i | i⁴ᵏ = 1, i⁴ᵏ⁺¹ = i, i⁴ᵏ⁺² = −1, i⁴ᵏ⁺³ = −i | Divide the power by 4 |
| Cube roots of unity | 1 + ω + ω² = 0; ω³ = 1 | ω¹⁰⁰ = ω |
| Quadratic | α + β = −b/a; αβ = c/a; D = b² − 4ac | "Sum is minus b by a" |
| AP | Tₙ = a + (n − 1)d; Sₙ = n/2[2a + (n − 1)d] | Sum = average × count |
| GP | Tₙ = arⁿ⁻¹; S∞ = a/(1 − r) | |r| < 1 for infinite sum |
| Means | AM ≥ GM ≥ HM; GM² = AM × HM | Alphabetical order reversed |
| P and C | ⁿPᵣ = n!/(n − r)!; ⁿCᵣ = n!/[r!(n − r)!] | Arrange = P, Choose = C |
| Circular | (n − 1)!; necklace (n − 1)!/2 | Fix one person |
| Binomial | T(r+1) = ⁿCᵣ xⁿ⁻ʳ yʳ; Σ coefficients = 2ⁿ | Put x = y = 1 |
| Logs | logₐ b = log b/log a; a^(logₐ x) = x | Change of base |
| Determinant | |kA| = kⁿ|A|; |adj A| = |A|ⁿ⁻¹; |AB| = |A||B| | Order n matters |
| 2 × 2 inverse | (1/(ad − bc)) [[d, −b], [−c, a]] | Swap diagonal, negate off-diagonal |
| Trig identities | sin² + cos² = 1; sec² − tan² = 1; cosec² − cot² = 1 | Pythagoras |
| Compound | sin(A + B) = sin A cos B + cos A sin B | "sin cos cos sin" |
| Double angle | cos 2A = 1 − 2 sin²A = 2 cos²A − 1 | Three forms |
| Max/min | a sin θ + b cos θ ∈ [−√(a² + b²), √(a² + b²)] | Hypotenuse of a, b |
| Triangle | a/sin A = 2R; a² = b² + c² − 2bc cos A | Sine rule, cosine rule |
| Inverse trig | sin⁻¹x + cos⁻¹x = π/2; tan⁻¹x + cot⁻¹x = π/2 | Complementary |
12. Master Summary Table
| Sub-topic | What NDA asks most | Typical Qs | Time-saving idea |
|---|---|---|---|
| Sets and functions | Counting subsets, relations, one-one functions, Venn problems | 4–6 | Use the inclusion–exclusion formula directly |
| Complex numbers | Powers of i, modulus/argument, ω-based simplification | 4–6 | Replace 1 + ω by −ω², 1 + ω² by −ω |
| Quadratics | Nature of roots, symmetric functions of roots, forming equations | 3–5 | Never solve for α, β separately |
| Sequences | nth term, sums, AM–GM–HM relations | 4–6 | Choose terms as a − d, a, a + d |
| P and C, Binomial | Word arrangements, committees, general/middle term | 5–8 | Set power of x = 0 for independent term |
| Matrices and determinants | Determinant properties, inverse, adjoint, system consistency | 8–12 | Use properties before expanding |
| Trigonometry | Identities, compound angles, max/min, inverse trig | 10–14 | Test with θ = 0°, 30°, 45° when options differ |
| Heights and distances | Single and two-position elevation problems | 2–4 | Draw the figure; use tan only |
13. Mind Map
- Sets, Venn diagrams
- Relations, functions
- Logarithms
- Complex numbers, ω
- Quadratic, cubic roots
- AP, GP, HP
- Permutations
- Combinations
- Binomial theorem
- Types, transpose
- Determinant properties
- Inverse, linear systems
- Identities, ASTC
- Compound, multiple angles
- Inverse trig, triangles
- Heights and distances
14. Tips and Tricks
- Substitute values: if an identity-based question has algebraic options, put θ = 45° or 30° (or x = 1, 2) and check which option survives.
- Use the options in quadratics: plug the options into the equation instead of solving it.
- Determinants: look for two equal or proportional rows/columns first — the answer is often 0.
- ω-problems: reduce every power of ω modulo 3 and use 1 + ω + ω² = 0.
- Binomial coefficients: the sum of coefficients is obtained by putting every variable equal to 1.
- Heights and distances: remember the "30–60" pattern: if angles are 30° and 60° and the observer walks d, height = (√3/2)d.
- Skip lengthy determinant expansions in the first round; come back after finishing the quick questions.
15. Important One-Liners
- The empty set is a subset of every set; a set with n elements has 2ⁿ subsets.
- i² = −1, i³ = −i, i⁴ = 1; the sum of four consecutive powers of i is 0.
- The modulus of a complex number is never negative; the argument of a positive real number is 0.
- A quadratic with real coefficients cannot have exactly one non-real root.
- If a + b + c = 0 in ax² + bx + c = 0, then 1 is a root.
- The AM of two positive numbers is always at least their GM.
- 0! = 1 by definition; ⁿC₀ = ⁿCₙ = 1.
- The number of terms in (a + b)ⁿ is n + 1.
- log 1 = 0 in every base; logarithm of a negative number is not defined (in reals).
- A square matrix with determinant zero is called singular and has no inverse.
- The determinant of an identity matrix is 1; of a skew-symmetric matrix of odd order is 0.
- Matrix multiplication is associative but not commutative.
- 1 radian ≈ 57.3°; π radians = 180°.
- sin θ and cos θ always lie between −1 and 1; tan θ can take any real value.
- tan 45° = 1, so at 45° elevation the height equals the horizontal distance.
- sin(90° − θ) = cos θ and tan(90° − θ) = cot θ.
- The period of sin x and cos x is 2π; of tan x is π.
- In a triangle, the largest side is opposite the largest angle.
16. PYQ-Based Questions with Detailed Answers
If A = {1, 2, 3, 4}, how many subsets of A contain the element 1?
- 4
- 8
- 12
- 16
Answer and explanation
Fix 1 inside the subset; each of the remaining 3 elements may be in or out, giving 2³ = 8 subsets. 16 is the total number of subsets of A (2⁴), and 4 and 12 do not follow from any counting rule here.
Answer: (B) 8
What is the value of i⁵⁷ + 1/i¹²⁵?
- 0
- 2i
- −2i
- 2
Answer and explanation
57 = 4 × 14 + 1, so i⁵⁷ = i. 125 = 4 × 31 + 1, so i¹²⁵ = i and 1/i = −i. The sum is i + (−i) = 0. Choosing 2i comes from forgetting that 1/i = −i.
Answer: (A) 0
If ω is a non-real cube root of unity, what is (1 + ω − ω²)(1 − ω + ω²)?
- 1
- 2
- 3
- 4
Answer and explanation
Using 1 + ω = −ω² and 1 + ω² = −ω: the first factor = −ω² − ω² = −2ω²; the second = −ω − ω = −2ω. Product = 4ω³ = 4. Expanding without these substitutions takes much longer and invites sign errors.
Answer: (D) 4
If α and β are the roots of x² − 5x + 6 = 0, what is α² + β²?
- 11
- 13
- 19
- 25
Answer and explanation
α + β = 5 and αβ = 6. α² + β² = (α + β)² − 2αβ = 25 − 12 = 13. Check: the roots are 2 and 3, and 4 + 9 = 13. 25 is (α + β)², a common slip.
Answer: (B) 13
The sum of the first 20 terms of the AP 3, 7, 11, ... is:
- 800
- 820
- 840
- 860
Answer and explanation
a = 3, d = 4, n = 20. S₂₀ = 20/2 [2 × 3 + 19 × 4] = 10 × [6 + 76] = 820. The 20th term is 79, and the average of first and last term is (3 + 79)/2 = 41, so the sum is 41 × 20 = 820 — the same answer by the "average × count" shortcut.
Answer: (B) 820
In how many ways can the letters of the word "DEFENCE" be arranged?
- 5040
- 840
- 720
- 210
Answer and explanation
DEFENCE has 7 letters with E repeated 3 times. Arrangements = 7!/3! = 5040/6 = 840. 5040 ignores the repetition; 210 would be 7!/4!, which does not match the letter counts.
Answer: (B) 840
What is the term independent of x in the expansion of (x² + 1/x)⁶?
- 15
- 20
- 6
- 1
Answer and explanation
T(r+1) = ⁶Cᵣ (x²)⁶⁻ʳ (1/x)ʳ = ⁶Cᵣ x^(12 − 3r). Setting 12 − 3r = 0 gives r = 4, so the term is ⁶C₄ = 15. 20 is ⁶C₃, which would be the answer for (x + 1/x)⁶, not this expression.
Answer: (A) 15
If A is a square matrix of order 3 with |A| = 4, what is |2A|?
- 8
- 16
- 24
- 32
Answer and explanation
|kA| = kⁿ|A| for order n. Here |2A| = 2³ × 4 = 32. Answer 8 comes from wrongly using 2|A|; the factor k multiplies every one of the 3 rows.
Answer: (D) 32
The points (1, 2), (3, 6) and (k, 10) are collinear. What is k?
- 4
- 5
- 6
- 7
Answer and explanation
Collinear points have equal slopes: slope between the first two = (6 − 2)/(3 − 1) = 2. Slope between (3, 6) and (k, 10) = 4/(k − 3) = 2 ⇒ k = 5. Equivalently, the area determinant is zero for k = 5.
Answer: (B) 5
What is the maximum value of 3 sin θ + 4 cos θ?
- 3
- 4
- 5
- 7
Answer and explanation
The maximum of a sin θ + b cos θ is √(a² + b²) = √(9 + 16) = 5. The value 7 (3 + 4) is never reached because sin θ and cos θ cannot both equal 1 at the same angle.
Answer: (C) 5
What is the value of sin 15° cos 15°?
- 1/4
- 1/2
- √3/4
- √3/2
Answer and explanation
sin A cos A = ½ sin 2A, so sin 15° cos 15° = ½ sin 30° = ½ × ½ = 1/4. √3/4 would result from mistakenly using cos 30°.
Answer: (A) 1/4
From a point on the ground, the angle of elevation of the top of a tower is 30°. On walking 40 m towards the tower, it becomes 60°. What is the height of the tower?
- 20 m
- 20√3 m
- 40 m
- 40√3 m
Answer and explanation
Let the height be h and the final distance x. tan 60° = h/x ⇒ h = x√3. tan 30° = h/(x + 40) ⇒ x + 40 = h√3 = 3x ⇒ x = 20, so h = 20√3 m (≈ 34.6 m). Shortcut for 30°–60°: h = (√3/2) × 40 = 20√3.
Answer: (B) 20√3 m
What is the value of sin⁻¹(3/5) + cos⁻¹(3/5)?
- 0
- π/4
- π/2
- π
Answer and explanation
For any x in [−1, 1], sin⁻¹x + cos⁻¹x = π/2, regardless of the value of x. The specific value 3/5 is a distraction.
Answer: (C) π/2
The general solution of tan θ = √3 is:
- θ = nπ + π/3
- θ = 2nπ + π/3
- θ = nπ + π/6
- θ = nπ ± π/3
Answer and explanation
tan θ = tan(π/3), and tangent repeats every π, so θ = nπ + π/3. 2nπ + π/3 misses the solutions in the third quadrant, and nπ ± π/3 is the solution of tan²θ = 3, which also includes tan θ = −√3.
Answer: (A) θ = nπ + π/3
The number of solutions of 2 sin²θ − 3 sin θ + 1 = 0 in the interval [0, 2π] is:
- 3
- 2
- 4
- 1
Answer and explanation
Factorising: (2 sin θ − 1)(sin θ − 1) = 0. sin θ = 1/2 gives θ = π/6 and 5π/6; sin θ = 1 gives θ = π/2. Three distinct solutions lie in [0, 2π].
Answer: (A) 3
The value of cos 20° × cos 40° × cos 80° is:
- 1/8
- 1/4
- √3/8
- 1/16
Answer and explanation
Multiply and divide by 2 sin 20° and apply 2 sin x cos x = sin 2x repeatedly: the product equals sin 160°/(8 sin 20°). Since sin 160° = sin 20°, the value is 1/8.
Answer: (A) 1/8
17. Quick Revision Summary
- Sets: 2ⁿ subsets, inclusion–exclusion, De Morgan; functions: nᵐ total, ⁿPₘ one-one.
- Complex numbers: powers of i cycle every 4; 1 + ω + ω² = 0; |z|² = z·z̄.
- Quadratics: discriminant decides roots; use α + β and αβ, never solve separately.
- Series: AP, GP sums; AM ≥ GM ≥ HM; standard sums Σn, Σn², Σn³.
- Counting: P for arrangement, C for selection; divide by factorials of repeated items; circular = (n − 1)!.
- Binomial: T(r+1) = ⁿCᵣ xⁿ⁻ʳ yʳ; set the power of x to 0 for the constant term.
- Matrices: |kA| = kⁿ|A|, |adj A| = |A|ⁿ⁻¹, inverse exists only if |A| ≠ 0.
- Trigonometry: standard angle table, ASTC, compound and double angles, max of a sin θ + b cos θ, sine and cosine rules.
- Heights and distances: tan(angle) = height/distance; draw the figure every time.