JEE Main Chemistry · Chapter 10

p-Block Elements

Groups 13 to 18 — inert pair effect, diborane, oxoacids of P and S, halogens, interhalogens and xenon compounds.

NCERT Class 11 & 12JEE Main: 1–2 Qs per shift 9 min read

1. Chapter at a Glance

The p-block contains groups 13 to 18, with outer configuration ns² np1–6. It has metals, metalloids, non-metals and the noble gases, so its chemistry is very varied. The current JEE syllabus covers groups 13 and 14 (Class 11) and groups 15 to 18 (Class 12). JEE Main typically asks about structures of oxoacids and interhalogen compounds, inert pair effect, anomalous behaviour of the first member, and properties of important compounds.

What JEE asks most
  • Inert pair effect: stability of lower oxidation states down the group (Tl⁺, Pb²⁺, Bi³⁺).
  • Structure of diborane, oxoacids of phosphorus and sulphur, and XeFn compounds.
  • Acid strength and thermal stability trends of hydrides (NH₃ to BiH₃, H₂O to H₂Te, HF to HI).
  • Interhalogen compounds and their shapes (VSEPR).

2. General Trends

  • Inert pair effect: down a group, the ns² electrons are less willing to take part in bonding (poor shielding by d and f electrons). So the lower oxidation state (group number − 2) becomes more stable: Tl⁺ > Tl³⁺, Pb²⁺ > Pb⁴⁺, Bi³⁺ > Bi⁵⁺. Hence PbO₂ and NaBiO₃ are strong oxidising agents.
  • First members (B, C, N, O, F) differ from the rest: small size, high electronegativity and no d orbitals — they can form pπ–pπ multiple bonds (N≡N, O=O, C=C) and their maximum covalency is 4.
  • Non-metallic character decreases down a group; metallic character increases.

3. Group 13: Boron Family (B, Al, Ga, In, Tl)

  • Boron is a non-metal; the others are metals. Common oxidation state +3; +1 becomes more stable for Tl.
  • Trihalides (BF₃, AlCl₃) are electron deficient Lewis acids. Lewis acidity: BF₃ < BCl₃ < BBr₃ (back-bonding from F's 2p to B's 2p is strongest in BF₃).
  • Borax, Na₂[B₄O₅(OH)₄]·8H₂O: gives the borax bead test with transition-metal oxides.
  • Boric acid, B(OH)₃: a weak monobasic Lewis acid — it accepts OH⁻ rather than donating H⁺: B(OH)₃ + H₂O → [B(OH)₄]⁻ + H⁺.
  • Diborane, B₂H₆: four terminal B–H bonds (2c–2e) and two bridging B–H–B bonds (3c–2e, "banana bonds"). Each B is sp³ hybridised.
  • Aluminium forms a protective oxide layer; Al₂O₃ is amphoteric.
BB HHHH HH terminal 2c–2ebridging 3c–2e (dashed)
Diborane, B₂H₆: four terminal B–H bonds lie in one plane; the two bridging hydrogens lie above and below that plane.

4. Group 14: Carbon Family (C, Si, Ge, Sn, Pb)

  • Oxidation states +4 and +2; +2 becomes more stable down the group (Pb²⁺). SnCl₂ is a reducing agent; PbO₂ is an oxidising agent.
  • Catenation (self-linking): C ≫ Si > Ge ≈ Sn; Pb does not catenate. C–C bond is strong.
  • Allotropes of carbon: diamond (sp³, 3D network, hardest, non-conductor), graphite (sp², layers, conducts electricity, lubricant), fullerenes (C₆₀, sp², soccer-ball shape with 20 hexagons and 12 pentagons).
  • CO is a neutral, poisonous gas that binds to haemoglobin; CO₂ is acidic and linear.
  • SiO₂ is a 3D network solid (each Si bonded tetrahedrally to four O). Silicones are polymers with –R₂SiO– units; they are water-repellent and heat-stable.
  • CCl₄ is not hydrolysed (C has no d orbitals), but SiCl₄ is readily hydrolysed to Si(OH)₄.

5. Group 15: Nitrogen Family (N, P, As, Sb, Bi)

  • Oxidation states −3 to +5. N₂ is very inert (N≡N bond energy 941 kJ mol−1).
  • Hydrides EH₃: basic strength and thermal stability decrease NH₃ > PH₃ > AsH₃ > SbH₃ > BiH₃; reducing power increases. Bond angle decreases: NH₃ (107°) > PH₃ (93.6°). Boiling point: NH₃ is high due to H-bonding, but SbH₃ has the highest.
  • Ammonia is made by the Haber process (Fe catalyst, Mo promoter, about 200 atm, 700 K). Nitric acid by the Ostwald process (Pt/Rh gauze catalyst oxidises NH₃ to NO).
  • Allotropes of phosphorus: white (P₄ tetrahedron, very reactive, glows in the dark, stored under water), red (polymeric, less reactive), black (most stable).
  • PCl₅ is trigonal bipyramidal in gas; in the solid it exists as [PCl₄]⁺[PCl₆]⁻.
Oxoacid of PFormulaP–OH groups (basicity)P–H bondsNature
HypophosphorousH₃PO₂12Strong reducing agent
PhosphorousH₃PO₃21Reducing; disproportionates on heating
OrthophosphoricH₃PO₄30Not reducing
PyrophosphoricH₄P₂O₇40P–O–P link

6. Group 16: Oxygen Family (O, S, Se, Te, Po)

  • Hydrides H₂E: acidic strength increases H₂O < H₂S < H₂Se < H₂Te (weaker H–E bond); thermal stability decreases. H₂O has the highest boiling point (H-bonding).
  • Ozone, O₃: bent molecule, a powerful oxidising agent; the ozone layer absorbs UV radiation.
  • Sulphur: rhombic (α, stable at room temperature) and monoclinic (β, above 369 K); both contain S₈ puckered crown rings.
  • Sulphuric acid by the contact process: 2SO₂ + O₂ ⇌ 2SO₃ using V₂O₅ catalyst; SO₃ is absorbed in H₂SO₄ to give oleum (H₂S₂O₇), which is then diluted.
  • Oxoacids of S: H₂SO₃, H₂SO₄, H₂S₂O₇ (pyrosulphuric, S–O–S), H₂SO₅ (Caro's acid, peroxide), H₂S₂O₈ (Marshall's acid, peroxide link).

7. Group 17: Halogens (F, Cl, Br, I, At)

  • Most reactive non-metals. Oxidising power: F₂ > Cl₂ > Br₂ > I₂. F shows only −1.
  • Bond dissociation enthalpy: Cl₂ > Br₂ > F₂ > I₂ (F₂ is low because of lone-pair repulsion in a short bond).
  • Acid strength of HX: HF < HCl < HBr < HI (bond strength decreases). HF is weak due to the strong H–F bond and H-bonding.
  • Acid strength of oxoacids of Cl: HOCl < HClO₂ < HClO₃ < HClO₄ (more O atoms stabilise the anion).
  • Interhalogen compounds: XX′ (ClF, linear), XX′₃ (ClF₃, T-shaped), XX′₅ (BrF₅, square pyramidal), XX′₇ (IF₇, pentagonal bipyramidal). They are more reactive than halogens (except F₂) because the X–X′ bond is weaker.
  • Chlorine bleaches by oxidation (in presence of moisture): permanent. SO₂ bleaches by reduction: temporary.

8. Group 18: Noble Gases

  • Stable ns² np⁶ configuration (He: 1s²); very low reactivity, high IE, positive electron gain enthalpy.
  • Neil Bartlett made O₂⁺[PtF₆]⁻ and, noting that Xe has nearly the same IE as O₂, made the first noble gas compound Xe⁺[PtF₆]⁻.
  • Xenon fluorides and shapes: XeF₂ (linear, sp³d), XeF₄ (square planar, sp³d²), XeF₆ (distorted octahedral, sp³d³). XeO₃ is pyramidal; XeOF₄ is square pyramidal.
  • Uses: He in balloons and diving gas (low solubility in blood); Ar in bulbs and welding; Ne in advertising signs.

9. Master Table: Shapes of Key p-Block Molecules

MoleculeBond pairs + lone pairsHybridisationShape
BF₃3 + 0sp²Trigonal planar
NH₃ / PH₃3 + 1sp³Pyramidal
SF₄4 + 1sp³dSee-saw
ClF₃3 + 2sp³dT-shaped
XeF₂ / I₃⁻2 + 3sp³dLinear
XeF₄4 + 2sp³d²Square planar
BrF₅5 + 1sp³d²Square pyramidal
IF₇7 + 0sp³d³Pentagonal bipyramidal

10. Mind Map

p-Block Elements
Groups 13–14
  • Diborane, boric acid
  • Allotropes of C
  • Silicones
Group 15
  • NH₃, HNO₃
  • Allotropes of P
  • Oxoacids of P
Group 16
  • Ozone
  • Contact process
  • Oxoacids of S
Groups 17–18
  • Interhalogens
  • HX acidity
  • Xenon fluorides

11. Tips and Tricks

Shortcuts
  • Basicity of a phosphorus oxoacid = number of P–OH groups, not the number of H atoms. P–H bonds make it a reducing agent.
  • Hydrides down a group: thermal stability ↓, reducing power ↑, acidity ↑ (for groups 16 and 17).
  • Use VSEPR: steric number = bond pairs + lone pairs; lone pairs go to equatorial positions in sp³d.
  • Inert pair effect: "heavy elements prefer (group − 2)".
Mistakes students make
  • Calling H₃PO₃ tribasic — it is dibasic (one H is bonded directly to P).
  • Thinking HF is the strongest halogen acid — it is the weakest in water.
  • Assuming BF₃ is the strongest Lewis acid among boron halides — BBr₃ is stronger because of weaker back-bonding.

12. Important One-liners

  • Diborane has two three-centre two-electron bonds.
  • Graphite conducts electricity because of delocalised π electrons.
  • White phosphorus is stored under water because it catches fire in air.
  • Oleum is H₂S₂O₇ (fuming sulphuric acid).
  • Fluorine has a lower bond dissociation enthalpy than chlorine.
  • XeF₄ is square planar with two lone pairs on Xe.

13. PYQ-pattern Questions with Solutions

These questions are original and modelled on concepts frequently tested in JEE Main.

Q1Easy

The basicity of H₃PO₃ is:

  1. 1
  2. 2
  3. 3
  4. 0
Show solution

H₃PO₃ has structure HP(O)(OH)₂: two ionisable P–OH groups and one non-ionisable P–H bond. Basicity = 2.

Answer: (B)

Q2Medium

The number of 3-centre-2-electron bonds in diborane is:

  1. 0
  2. 2
  3. 4
  4. 6
Show solution

B₂H₆ has 4 terminal B–H (2c–2e) bonds and 2 bridging B–H–B (3c–2e) bonds.

Answer: (B)

Q3Medium

The shape of XeF₄ is:

  1. Tetrahedral
  2. See-saw
  3. Square planar
  4. Square pyramidal
Show solution

Xe has 8 valence electrons: 4 used in bonds and 4 left as 2 lone pairs. Steric number 6 (sp³d²); the two lone pairs sit opposite each other, so the shape is square planar.

Answer: (C)

Q4Easy

The strongest acid in aqueous solution among the following is:

  1. HF
  2. HCl
  3. HBr
  4. HI
Show solution

Acid strength depends on how easily H–X breaks. The H–I bond is the weakest (largest atom), so HI is the strongest acid.

Answer: (D)

Q5Hard

Which of the following is the strongest oxidising agent because of the inert pair effect?

  1. SnO₂
  2. PbO₂
  3. SiO₂
  4. CO₂
Show solution

For lead, +2 is more stable than +4 (inert pair effect), so Pb⁴⁺ in PbO₂ readily gains electrons to become Pb²⁺. It is a strong oxidising agent. Sn⁴⁺, Si⁴⁺ and C⁴⁺ are stable in the +4 state.

Answer: (B)

Q6Hard

The shape of ClF₃ is:

  1. Trigonal planar
  2. Pyramidal
  3. T-shaped
  4. See-saw
Show solution

Cl has 7 valence electrons: 3 bond pairs and 2 lone pairs (steric number 5, sp³d). The lone pairs occupy two equatorial positions, leaving a T-shaped molecule.

Answer: (C)

Q7Medium

Which hydride has the lowest thermal stability?

  1. NH₃
  2. PH₃
  3. AsH₃
  4. BiH₃
Show solution

Down group 15, the central atom becomes bigger and the E–H bond weaker. BiH₃ has the weakest bond and is the least stable.

Answer: (D)

Q8Numerical

Find the total number of lone pairs on the central atoms in XeF₂, XeF₄ and XeF₆ taken together.

Show solution

Xe has 8 valence electrons. XeF₂: 2 used, 6 left = 3 lone pairs. XeF₄: 4 used = 2 lone pairs. XeF₆: 6 used = 1 lone pair. Total = 3 + 2 + 1 = 6.

Answer: 6

14. Quick Revision Summary

Remember before the exam
  • Inert pair effect: Tl⁺, Pb²⁺, Bi³⁺ are stable; PbO₂ and NaBiO₃ oxidise.
  • Diborane: 2 banana bonds; boric acid is a monobasic Lewis acid.
  • H₃PO₂ monobasic, H₃PO₃ dibasic, H₃PO₄ tribasic.
  • HX acid strength: HI > HBr > HCl > HF; oxoacids: HClO₄ strongest.
  • Bond enthalpy: Cl₂ > Br₂ > F₂ > I₂.
  • XeF₂ linear, XeF₄ square planar, XeF₆ distorted octahedral.