NEET UG Chemistry · Chapter 14

Organic Chemistry: Basic Principles and Techniques

Nomenclature, isomerism, electronic effects, reaction intermediates, purification and analysis of organic compounds.

NCERT Class 11NEET: 2 Qs per paper 10 min read

1. Chapter at a Glance

This chapter is the grammar of organic chemistry. It explains the special nature of carbon, how organic compounds are named (IUPAC), the kinds of isomerism, the electronic effects that control reactivity (inductive, resonance, hyperconjugation, electromeric), reaction intermediates (carbocations, carbanions, free radicals), and the types of reagents and reactions. It also covers methods of purifying and analysing organic compounds. NEET asks about two questions from here every year, and its ideas are needed for every later organic chapter.

What NEET asks most
  • IUPAC names of compounds with functional groups and branches.
  • Structural and stereo-isomerism; counting isomers.
  • Stability order of carbocations, carbanions and free radicals.
  • Inductive, resonance (±R) and hyperconjugation effects; acidity and basicity comparisons.
  • Purification (distillation types, chromatography) and quantitative analysis (Kjeldahl, Carius, Dumas).

2. Tetravalence of Carbon and Structural Representation

  • Carbon forms four covalent bonds. Its hybridisation decides the shape: sp³ (tetrahedral, 109.5°), sp² (trigonal planar, 120°), sp (linear, 180°).
  • Electronegativity of carbon rises with s-character: sp > sp² > sp³. That is why the terminal H of ethyne is weakly acidic.
  • Structures can be written as complete (dash) formulas, condensed formulas (CH₃CH₂OH) or bond-line (zig-zag) formulas, where each corner or end is a carbon.
  • Homologous series: members differ by –CH₂–, have the same general formula and similar chemical properties.

3. IUPAC Nomenclature

  1. Choose the longest carbon chain that contains the principal functional group and the maximum number of multiple bonds.
  2. Number the chain to give the principal functional group the lowest locant, then multiple bonds, then substituents.
  3. Name substituents alphabetically as prefixes (ignoring di-, tri- when alphabetising).
  4. Add the suffix for the principal functional group.
Priority (high → low)SuffixPrefix
Carboxylic acid-oic acidcarboxy
Sulphonic acid-sulphonic acidsulpho
Ester-oatealkoxycarbonyl
Acid chloride-oyl chloridechlorocarbonyl
Amide-amidecarbamoyl
Nitrile-nitrilecyano
Aldehyde-alformyl / oxo
Ketone-oneoxo
Alcohol-olhydroxy
Amine-amineamino
Alkene / alkyne-ene / -yne—

Groups always named as prefixes: halo (–X), nitro (–NO₂), alkoxy (–OR). Example: CH₃CH(OH)CH₂COOH is 3-hydroxybutanoic acid.

4. Isomerism

  • Structural isomerism: chain (different carbon skeleton), position (different position of a group), functional (different functional group, e.g. ethanol and dimethyl ether), metamerism (different alkyl groups around the same functional group, e.g. diethyl ether and methyl propyl ether), and tautomerism (keto–enol).
  • Stereoisomerism: same connectivity, different arrangement in space.
  • Geometrical (cis–trans): needs restricted rotation (C=C or a ring) and two different groups on each doubly bonded carbon.
  • Optical: a chiral molecule (usually with a carbon bearing four different groups) is non-superimposable on its mirror image. Enantiomers rotate plane-polarised light equally in opposite directions; a 50 : 50 mixture (racemic) is optically inactive.
  • Maximum number of optical isomers = 2ⁿ for n different chiral centres (fewer if a meso form exists).

5. Electronic Effects

EffectWhat happensExamplesNEET Note
Inductive (−I)Electron withdrawal through σ bonds–NO₂ > –CN > –COOH > –F > –Cl > –Br > –I > –OHWeakens with distance
Inductive (+I)Electron release through σ bonds(CH₃)₃C– > (CH₃)₂CH– > CH₃CH₂– > CH₃–Alkyl groups
Resonance (+R/+M)Lone pair donated into a π system–OH, –OR, –NH₂, –XMakes ring electron-rich
Resonance (−R/−M)π electrons pulled out of the system–NO₂, –CHO, –COOH, –CNMakes ring electron-poor
HyperconjugationC–H σ electrons delocalise into an adjacent empty p or π* orbitalAlkyl carbocations, alkenesMore α-H ⇒ more stable
ElectromericTemporary shift of π electrons when a reagent attacksC=O, C=CDisappears when reagent removed
  • Acidity increases when the conjugate base is stabilised: electron-withdrawing groups raise acidity (Cl₃CCOOH > Cl₂CHCOOH > ClCH₂COOH > CH₃COOH).
  • Basicity of amines rises with electron-donating groups and falls when the lone pair is delocalised (aniline is weaker than methylamine).

6. Reaction Intermediates and Reagents

  • Homolytic cleavage gives free radicals; heterolytic cleavage gives carbocations and carbanions.
  • Carbocation (sp², planar, electron-deficient): stability 3° > 2° > 1° > CH₃⁺, because of +I and hyperconjugation. Allyl and benzyl carbocations are extra stable because of resonance. Carbocations can rearrange (hydride or methyl shift) to a more stable form.
  • Carbanion (sp³, pyramidal, electron-rich): stability CH₃⁻ > 1° > 2° > 3° (alkyl groups push in more electrons).
  • Free radical (sp², one unpaired electron): stability 3° > 2° > 1° > CH₃•.
  • Carbene: neutral, divalent carbon (:CH₂).
  • Electrophiles are electron-seeking (H⁺, NO₂⁺, Br⁺, AlCl₃, BF₃, carbocations); nucleophiles are electron-rich (OH⁻, CN⁻, NH₃, H₂O, RO⁻).
  • Reaction types: substitution, addition, elimination and rearrangement.
CH₃⁺ 1° 2° 3° stability increases → (+I effect and hyperconjugation)
Carbocation stability: 3° > 2° > 1° > methyl. Each extra alkyl group donates electron density and adds hyperconjugation structures.

7. Purification and Analysis

MethodUsed forExample
SublimationSolids that change directly to vapourCamphor, naphthalene, benzoic acid
CrystallisationSolid with an impurity of different solubilitySugar, benzoic acid from water
Simple distillationLiquids with a large difference in boiling pointChloroform (334 K) and aniline (457 K)
Fractional distillationLiquids with close boiling pointsCrude oil fractions
Distillation under reduced pressureLiquids that decompose below their boiling pointGlycerol from spent lye
Steam distillationSteam-volatile, water-immiscible liquidsAniline, essential oils
Differential extractionCompound more soluble in an organic solventSeparating funnel
ChromatographySeparation by different adsorption or partitionColumn, TLC (Rf), paper chromatography
  • Lassaigne's test (sodium fusion) detects N (Prussian blue), S (violet with sodium nitroprusside; black PbS), and halogens (AgX precipitates). If both N and S are present, a blood-red colour with Fe³⁺ appears (thiocyanate).
  • Kjeldahl's method (% N): N is converted to ammonium sulphate, NH₃ is released and absorbed in a known volume of standard acid, and %N = 1.4 × (normality × volume in mL of acid used by NH₃)/mass of compound. It does not work for nitro, azo compounds or N in rings (pyridine).
  • Dumas method (% N): N converted to N₂ gas and its volume measured.
  • Carius method: halogens and sulphur estimated as AgX and BaSO₄.
  • Rf = distance moved by the substance/distance moved by the solvent front.

8. Formula and Rule Master Table

QuantityFormula / rule
Optical isomers2ⁿ (n = different chiral centres)
Carbocation / radical stability3° > 2° > 1° > CH₃
Carbanion stabilityCH₃ > 1° > 2° > 3°
Electronegativity of Csp > sp² > sp³
Rf valuedistance of spot/distance of solvent front
% halogen (Carius)(atomic mass X/M of AgX) × (mass AgX/mass compound) × 100
% S (Carius)(32/233) × (mass BaSO₄/mass compound) × 100
% N (Kjeldahl)1.4 × (meq of acid used by NH₃)/mass of compound

9. Master Summary Table

ConceptKey ideaNEET Note
IUPACPrincipal group gets lowest locantAcid > ester > aldehyde > ketone > alcohol
Geometrical isomerismRestricted rotationEach C of C=C needs two different groups
Optical isomerismChiralityRacemic mixture inactive
−I groupsIncrease acidityNO₂ strongest
HyperconjugationMore α-H, more stableAlso called no-bond resonance
Carbocationsp², planarRearranges to more stable ion
Steam distillationImmiscible, steam-volatileAniline
Kjeldahl% NNot for nitro or ring N

10. Mind Map

Organic Basics
Naming and isomers
  • IUPAC priority
  • Structural
  • Stereo
Electronic effects
  • ±I
  • ±R
  • Hyperconjugation
Intermediates
  • Carbocation
  • Carbanion, radical
  • Nu⁻ and E⁺
Techniques
  • Purification
  • Lassaigne
  • Estimation

11. Tips and Tricks

Shortcuts
  • For acid strength, look at how stable the anion is: resonance > −I groups close to COOH > −I groups far away.
  • Number of hyperconjugation structures = number of α-hydrogens.
  • To decide chirality, look for carbon with four different groups; check for a mirror plane (meso) if there are two chiral centres.
  • Degree of unsaturation = (2C + 2 + N − H − X)/2 — each ring or π bond counts 1.
Common NEET traps
  • Giving the carbanion stability order the same as carbocations.
  • Numbering from the end nearer a substituent instead of the principal functional group.
  • Calling a racemic mixture optically active.
  • Applying Kjeldahl's method to nitrobenzene.

12. Important One-liners

  • Carbocations are sp² hybridised and planar.
  • The tert-butyl carbocation is more stable than the isopropyl carbocation.
  • Benzyl and allyl carbocations are stabilised by resonance.
  • Ethanol and methoxymethane are functional isomers.
  • Aniline is purified by steam distillation.
  • Glycerol is purified by distillation under reduced pressure.
  • A blood-red colour in Lassaigne's test shows that both N and S are present.
  • BF₃ and AlCl₃ are electrophiles; NH₃ and H₂O are nucleophiles.

13. NEET-pattern Questions with Detailed Answers

These questions are original and based on concepts that NEET UG asks again and again.

Q1Easy

The IUPAC name of CH₃–CH(CH₃)–CH₂–OH is:

  1. 2-Methylpropan-1-ol
  2. Butan-1-ol
  3. 2-Methylpropan-3-ol
  4. Isobutanol-1
Show solution

The longest chain containing the carbon with the OH group has 3 carbons. Numbering from the OH end puts the OH on C-1 and the methyl on C-2. (C) numbers from the wrong end, (B) ignores the branch, and (D) is not an IUPAC name.

Answer: (A)

Q2Easy

The most stable carbocation among these is:

  1. CH₃⁺
  2. CH₃CH₂⁺
  3. (CH₃)₂CH⁺
  4. (CH₃)₃C⁺
Show solution

The tertiary carbocation has the most +I donation and 9 hyperconjugating α-hydrogens, so it is the most stable. CH₃⁺ is the least stable.

Answer: (D)

Q3Medium

Which is the strongest acid?

  1. CH₃COOH
  2. ClCH₂COOH
  3. Cl₂CHCOOH
  4. Cl₃CCOOH
Show solution

Each Cl pulls electrons away (−I) and stabilises the carboxylate anion. Three Cl atoms give the greatest stabilisation, so trichloroacetic acid is the strongest acid.

Answer: (D)

Q4Medium

Which compound shows geometrical isomerism?

  1. CH₂=CHCl
  2. CH₃CH=CHCH₃
  3. (CH₃)₂C=CH₂
  4. CH₂=CH₂
Show solution

In but-2-ene, each double-bonded carbon carries two different groups (H and CH₃), so cis and trans forms exist. In the other three compounds, at least one carbon has two identical groups.

Answer: (B)

Q5Medium

The number of hyperconjugation structures possible for the isopropyl carbocation, (CH₃)₂CH⁺, is:

  1. 3
  2. 6
  3. 9
  4. 2
Show solution

The number of structures equals the number of α-hydrogens. Two CH₃ groups give 6. The tert-butyl cation would have 9 and the ethyl cation 3.

Answer: (B)

Q6Medium

A mixture of chloroform (b.p. 334 K) and aniline (b.p. 457 K) is best separated by:

  1. Simple distillation
  2. Steam distillation
  3. Sublimation
  4. Crystallisation
Show solution

The boiling points differ by more than 100 K, so simple distillation works. Steam distillation is used to separate aniline from water-insoluble, non-volatile impurities, which is a different situation.

Answer: (A)

Q7Hard

The number of optical isomers of 2,3-dihydroxybutanedioic acid (tartaric acid) is:

  1. 4
  2. 3
  3. 2
  4. 1
Show solution

There are two chiral centres, but they carry identical groups. So instead of 2² = 4 isomers, there are two optically active enantiomers (d and l) plus one meso form, which is inactive. That makes 3 stereoisomers.

Answer: (B)

Q8Hard

Kjeldahl's method cannot be used to estimate nitrogen in:

  1. Urea
  2. Acetamide
  3. Nitrobenzene
  4. Aniline
Show solution

Nitrogen in nitro groups, azo groups and ring positions (pyridine) is not converted into ammonium sulphate under Kjeldahl conditions. Urea, acetamide and aniline all give NH₃ properly.

Answer: (C)

14. Quick Revision Summary

Remember before the exam
  • IUPAC: longest chain with principal group; lowest locant to it; prefixes alphabetical.
  • Isomers: chain, position, functional, metamer, tautomer; cis–trans; optical (2ⁿ, minus meso).
  • −I/−R raise acidity; +I/+R and hyperconjugation stabilise cations.
  • Carbocation/radical 3° > 2° > 1°; carbanion reverse.
  • Purification by b.p. difference, steam, reduced pressure, chromatography; Lassaigne, Kjeldahl, Carius.