Class 7 Mathematics · Chapter 14 · Part II

Constructions and Tilings

Constructions with ruler and compass, regular polygons and tiling patterns (tessellations).

NCERT Ganita Prakash (Part I and Part II)CBSE Class 7 9 min read

1. Chapter at a Glance

With only a ruler and compass, you can bisect a line, bisect an angle and draw angles of 60°, 90°, 30° and 45° — no protractor needed. With repeated shapes, you can cover a floor completely without gaps or overlaps, like the tiles in your home or the patterns in rangoli and temple floors. This chapter combines both ideas: precise constructions and tilings (tessellations).

What you will learn
  • Constructing the perpendicular bisector of a segment.
  • Constructing the bisector of an angle.
  • Constructing 60°, 120°, 90°, 30° and 45° angles with a compass.
  • Drawing a regular hexagon inside a circle.
  • Tilings: which shapes tile a plane and why angles at a point must add to 360°.
  • Regular and semi-regular tilings in art and architecture.

2. Perpendicular Bisector of a Segment

The perpendicular bisector of AB is the line that passes through the midpoint of AB at 90°. Every point on it is equally far from A and B.

  1. Draw AB. Open the compass to more than half of AB.
  2. With centre A, draw arcs above and below AB.
  3. With centre B and the same radius, draw arcs cutting the first arcs at P and Q.
  4. Join PQ. It meets AB at M, the midpoint, and PQ ⊥ AB.
AB PQM AM = MB, PQ ⊥ AB
Equal arcs from A and B meet at P and Q; PQ is the perpendicular bisector of AB.

3. Bisecting an Angle

To bisect ∠ABC (divide it into two equal angles):

  1. With centre B and any radius, draw an arc cutting BA at P and BC at Q.
  2. With centres P and Q and the same radius (more than half of PQ), draw arcs meeting at R inside the angle.
  3. Join BR. It is the angle bisector: ∠ABR = ∠RBC.

Why it works: ΔBPR and ΔBQR are congruent by SSS (BP = BQ, PR = QR, BR common), so the two angles at B are equal.

4. Constructing Special Angles

AngleMethod
60°Draw an arc from O cutting the ray at P; from P with the same radius cut the arc at Q. ∠POQ = 60° (ΔOPQ is equilateral).
120°Step the same radius once more along the arc from Q to R. ∠POR = 120°.
30°Bisect 60°.
90°Bisect the angle between the 60° and 120° marks, or construct the perpendicular at a point.
45°Bisect 90°.
15°, 75°, 135°Bisect 30°; 60° + 15°; 90° + 45°.

Regular hexagon in a circle

Draw a circle. Keep the compass at the same radius and step around the circle starting from any point — exactly six steps return to the start. Joining the six points gives a regular hexagon whose side equals the radius (it is made of six equilateral triangles).

5. Tilings (Tessellations)

A tiling covers a flat surface with shapes that fit together with no gaps and no overlaps. Where tiles meet at a point, the angles around that point must add up to exactly 360°.

Which regular polygons tile alone?

Regular polygonEach interior angle360° ÷ angleTiles alone?
Equilateral triangle60°6Yes
Square90°4Yes
Regular pentagon108°3.33…No
Regular hexagon120°3Yes
Regular octagon135°2.67…No

Only three regular polygons — the triangle, square and hexagon — tile a plane by themselves. Bees use hexagons in honeycombs because hexagons tile without gaps and use the least wax for a given area.

6 × 60° = 360°4 × 90° = 360°3 × 120° = 360°
The three regular tilings: six triangles, four squares or three hexagons meet at each point, always making 360°.

Semi-regular tilings and art

Different regular polygons can be combined: two octagons and a square fit at a point (135° + 135° + 90° = 360°), a pattern often seen on floors. Triangles and hexagons, or squares and triangles, also combine. Indian architecture — from step-wells to temple floors and jali screens — and rangoli patterns use such tilings beautifully.

Any triangle and any quadrilateral (even irregular ones) can tile the plane, because their angles can be arranged to make 360° at every point (a quadrilateral's angles add to 360°; two copies of a triangle's angles make 360°).

6. Solved Problems (NCERT Style)

Problem 1 — Constructing 75°

How can you construct a 75° angle with ruler and compass only?

Solution: Construct 60° and 90° at the same point on the same ray, then bisect the angle between them (30°) to get 15°. 60° + 15° = 75°.

Problem 2 — Does this combination tile?

Can one regular hexagon and two squares meet at a point in a tiling?

Solution: 120° + 90° + 90° = 300° ≠ 360°. A gap of 60° remains, which an equilateral triangle could fill (hexagon + 2 squares + triangle = 360°). Alone, the three shapes do not close the gap.

Problem 3 — Midpoint without measuring

Find the midpoint of a 7.3 cm segment without measuring.

Solution: Construct its perpendicular bisector; where it cuts the segment is the midpoint (3.65 cm from each end).

7. Master Formula Table

FactRule
Perpendicular bisectorpoints equidistant from A and B
Angle bisectordivides angle into two equal parts
60° with compassequilateral triangle from equal radii
90°, 45°, 30°, 15°bisect 180°, 90°, 60°, 30°
Hexagon side in a circle= radius
Tiling conditionangles at a point = 360°
Interior angle of regular n-gon180° × (n − 2) ÷ n
Regular tilingsonly n = 3, 4, 6

8. Master Summary Table

TopicKey ideaExam focus
Perpendicular bisectorEqual arcs from both endsMidpoint, equidistance
Angle bisectorArcs from points on armsBisect given angles
Special angles60° base, then bisect30°, 45°, 75°, 135°
HexagonSix radii around a circleConstruction steps
TilingsNo gaps, no overlaps; 360°Which shapes tile

9. Mind Map

Constructions and Tilings
Bisectors
  • Of a segment
  • Of an angle
Angles
  • 60°, 120°
  • 90°, 45°, 30°
Polygons
  • Hexagon in circle
  • Interior angles
Tilings
  • 360° at a point
  • Triangles, squares, hexagons
  • Semi-regular patterns

10. Tips and Tricks

Smart ideas
  • Keep construction arcs visible — examiners award marks for method.
  • Use a radius more than half the segment, or the arcs won't meet.
  • To test a tiling, add the angles meeting at one point — they must total 360°.
Common mistakes
  • Changing the compass radius between the two arcs.
  • Thinking regular pentagons can tile a floor alone.
  • Bisecting 60° and calling it 45°.

11. Important One-liners

  • The perpendicular bisector of a segment passes through its midpoint at 90°.
  • An angle bisector splits an angle into two equal angles.
  • Equal compass steps from a point on a circle make 60° at the centre.
  • The side of a regular hexagon in a circle equals the radius.
  • Angles meeting at a point in a tiling add up to 360°.
  • Only equilateral triangles, squares and regular hexagons tile by themselves.
  • Every triangle and every quadrilateral can tile the plane.

12. Exam-pattern Questions with Detailed Answers

Q1Easy

Which regular polygon CANNOT tile a floor by itself?

  1. Square
  2. Equilateral triangle
  3. Regular pentagon
  4. Regular hexagon
Show answer

Its angle 108° does not divide 360° exactly (360 ÷ 108 is not whole).

Answer: (C)

Q2Easy

Which angle do you get by bisecting a 90° angle?

Show answer

Half of 90° is 45°.

Answer: 45°

Q3Easy

How many equilateral triangles meet at a point in a triangular tiling?

Show answer

360° ÷ 60° = 6.

Answer: 6

Q4Medium

Write the steps to construct a 135° angle.

Show answer

On a straight line through O, construct the perpendicular (90°). Bisect the 90° angle on the other side, between the perpendicular and the ray going the other way, to get 45°. 90° + 45° = 135°.

Answer: 90° + bisected 90° (45°) = 135°

Q5Medium

Find the interior angle of a regular octagon and check whether two octagons and a square can meet at a point.

Show answer

Interior angle = 180° × 6 ÷ 8 = 135°. 135° + 135° + 90° = 360° ✔.

Answer: 135°; yes, they fit

Q6Medium

A circle has radius 4 cm. What is the perimeter of the regular hexagon constructed inside it with compass steps?

  1. 16 cm
  2. 24 cm
  3. 32 cm
  4. 12 cm
Show answer

Side = radius = 4 cm; perimeter = 6 × 4 = 24 cm.

Answer: (B) 24 cm

Q7Medium

Why is every point on the perpendicular bisector of AB equidistant from A and B?

Show answer

For a point P on it, with M the midpoint: ΔPMA ≅ ΔPMB by SAS (AM = BM, ∠PMA = ∠PMB = 90°, PM common). So PA = PB.

Answer: By SAS congruence

Q8Medium

How many squares and triangles meet at a point if 2 squares are used and the rest are equilateral triangles?

Show answer

2 × 90° = 180°; remaining 180° ÷ 60° = 3 triangles. So 2 squares and 3 triangles.

Answer: 3 triangles

Q9Hard

Show that a regular 12-gon (angle 150°) and an equilateral triangle can meet at a point. How many of each?

Show answer

Two 12-gons: 300°; one triangle: 60°; total 360° ✔.

Answer: Two 12-gons and one triangle

Q10Hard

Explain why any quadrilateral can tile the plane.

Show answer

The four angles of any quadrilateral add to 360°. By rotating copies through half-turns about the midpoints of the sides, the four different angles can be placed around each vertex, filling exactly 360° with no gap.

Answer: Its angles sum to 360°, which fills a point exactly

Q11Hard

Using only compass steps, how would you construct a 150° angle?

Show answer

Construct 120° (two 60° steps), then construct 30° beyond it by bisecting the next 60° step (from 120° to 180°). 120° + 30° = 150°.

Answer: 120° + 30° = 150°

Q12Hard

Why do honeycombs use hexagons rather than triangles or squares, if all three tile?

Show answer

Among shapes that tile, the regular hexagon encloses the largest area for a given perimeter, so the bees use the least wax for storage space. It is also strong and closest to a circle.

Answer: Maximum space for the least wall material

13. Quick Revision Summary

Revise in 2 minutes
  • Perpendicular bisector: equal arcs from both ends; gives midpoint and equidistant points.
  • Angle bisector: arcs on the arms, then equal arcs inside; proved by SSS.
  • 60° from equal compass steps; bisect for 30°, 90°, 45°, 15°.
  • Hexagon in a circle: six steps of the radius.
  • Tiling: angles at a point = 360°; regular triangles, squares, hexagons tile alone.