Class 7 Mathematics · Chapter 9 · Part II

Geometric Twins

Congruent figures, congruence of triangles and the SSS, SAS, ASA and RHS criteria.

NCERT Ganita Prakash (Part I and Part II)CBSE Class 7 10 min read

1. Chapter at a Glance

Two ₹10 coins, two stamps from the same sheet, or the two blades of a pair of scissors — such objects have exactly the same shape and size. In geometry, figures that are exact copies of each other are called congruent ("geometric twins"). One can be placed on the other so that they cover each other completely. In this chapter you will learn what congruence means, how to match the parts of congruent figures, and the four short tests — SSS, SAS, ASA and RHS — that tell us when two triangles are congruent without checking every part.

What you will learn
  • The meaning of congruence and the symbol ≅.
  • Congruent line segments, angles and figures.
  • Corresponding parts of congruent triangles.
  • Congruence criteria: SSS, SAS, ASA (and AAS) and RHS.
  • Why SSA and AAA are not valid tests.
  • Using congruence to prove facts and solve problems.

2. What is Congruence?

Two figures are congruent if one can be moved (slid, turned or flipped) so that it fits exactly on the other. We write ≅ for "is congruent to".

  • Line segments are congruent if they have the same length: AB ≅ CD when AB = CD.
  • Angles are congruent if they have the same measure.
  • Circles are congruent if they have the same radius.
  • Squares are congruent if they have the same side.

Congruent figures have the same shape and the same size. Figures with the same shape but different sizes (like a photo and its enlargement) are similar, not congruent.

Worked Example 1

Are two rectangles 6 cm × 4 cm and 4 cm × 6 cm congruent?

Solution: Yes. Turning one through 90° makes it fit exactly on the other — it is the same rectangle in a different position.

3. Congruent Triangles and Corresponding Parts

Two triangles are congruent if all three sides and all three angles of one are equal to the matching sides and angles of the other. The matching is called a correspondence. If ΔABC ≅ ΔPQR, then A ↔ P, B ↔ Q, C ↔ R, and:

AB = PQ, BC = QR, CA = RP;   ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R

The order of the letters matters. Writing ΔABC ≅ ΔQPR would claim A matches Q, which may be wrong.

Once two triangles are known to be congruent, all their corresponding parts are equal. This is often written as CPCT — corresponding parts of congruent triangles.

4. Congruence Criteria

We don't need all six equalities. Certain three of them are enough to guarantee congruence, because those three already fix the triangle completely (as you saw in constructions).

CriterionWhat is equalWhy it works
SSSAll three sidesThree sides fix the triangle (arcs construction)
SASTwo sides and the angle between themThe included angle fixes the third side
ASATwo angles and the side between themRays from the ends of the side meet at one point
AASTwo angles and a non-included sideThe third angle is fixed by the angle sum, so it becomes ASA
RHSRight angle, hypotenuse and one sideFor right triangles only
ABC PQR Matching tick marks show equal sides: ΔABC ≅ ΔPQR (SSS)
Equal sides are marked with the same number of ticks. Three pairs of equal sides make the triangles congruent by SSS.
Tests that do NOT work
  • AAA: equal angles only fix the shape, not the size (a small and a large equilateral triangle).
  • SSA (two sides and a non-included angle): two different triangles may fit the same data, so it does not guarantee congruence. (RHS is the special case where it does work, because the angle is 90°.)

5. Using Congruence

Congruence lets us prove that lengths or angles are equal without measuring.

Worked Example 2 — Isosceles triangle

In ΔABC, AB = AC. Show that ∠B = ∠C.

Solution: Let D be the midpoint of BC and join AD. In ΔABD and ΔACD: AB = AC (given), BD = CD (D is the midpoint), AD = AD (common). So ΔABD ≅ ΔACD by SSS. Hence ∠B = ∠C (CPCT). This proves that the angles opposite equal sides are equal.

Worked Example 3 — Measuring across a river

To find the width AB of a pond, a surveyor marks a point O, extends AO to C so that OC = OA, and BO to D so that OD = OB. Why is CD equal to AB?

Solution: In ΔAOB and ΔCOD: OA = OC, OB = OD, and ∠AOB = ∠COD (vertically opposite). So ΔAOB ≅ ΔCOD by SAS, and AB = CD (CPCT). Measuring CD on land gives the pond's width.

6. Solved Problems (NCERT Style)

Problem 1 — Which criterion?

In ΔDEF and ΔXYZ, DE = XY, ∠E = ∠Y and EF = YZ. Are they congruent? Which criterion?

Solution: ∠E lies between sides DE and EF, and ∠Y between XY and YZ. Two sides and the included angle match, so ΔDEF ≅ ΔXYZ by SAS.

Problem 2 — Writing the correspondence

ΔLMN ≅ ΔSTU. Write all the equal parts.

Solution: L ↔ S, M ↔ T, N ↔ U. Sides: LM = ST, MN = TU, NL = US. Angles: ∠L = ∠S, ∠M = ∠T, ∠N = ∠U.

Problem 3 — Right triangles

Two right triangles each have hypotenuse 13 cm and one side 5 cm. Are they congruent?

Solution: Yes, by RHS (right angle, hypotenuse, side). Both third sides will be 12 cm.

Problem 4 — A kite

In kite ABCD, AB = AD and CB = CD. Show that the diagonal AC bisects ∠A.

Solution: In ΔABC and ΔADC: AB = AD, CB = CD, AC common. So they are congruent by SSS, and ∠BAC = ∠DAC (CPCT). Hence AC bisects ∠A.

7. Master Formula Table

CriterionCondition
SSS3 sides equal
SAS2 sides + included angle
ASA2 angles + included side
AAS2 angles + a matching non-included side
RHSright angle + hypotenuse + one side
Not validAAA, SSA
CPCTcongruent ⇒ all matching parts equal

8. Master Summary Table

TopicKey ideaExam focus
CongruenceSame shape and sizeIdentify congruent figures
CorrespondenceOrder of vertices mattersWrite equal parts
CriteriaSSS, SAS, ASA/AAS, RHSChoose the right one
Invalid testsAAA, SSAExplain why
ApplicationsProve equal lengths and anglesIsosceles, kite, surveying

9. Mind Map

Geometric Twins
Meaning
  • Same shape and size
  • Symbol ≅
Matching
  • Correspondence
  • CPCT
Criteria
  • SSS, SAS
  • ASA, AAS
  • RHS
Uses
  • Isosceles base angles
  • Distances across rivers

10. Tips and Tricks

Smart ideas
  • Mark equal sides with ticks and equal angles with arcs before choosing a criterion.
  • Look for a common side shared by both triangles and for vertically opposite angles — free equal parts.
  • In SAS, check that the angle is between the two sides.
Common mistakes
  • Writing the congruence with vertices in the wrong order.
  • Using SSA or AAA as a congruence test.
  • Confusing congruent (same size) with similar (same shape only).

11. Important One-liners

  • Congruent figures have the same shape and size.
  • Line segments are congruent if their lengths are equal.
  • Angles are congruent if their measures are equal.
  • In ΔABC ≅ ΔPQR, A matches P, B matches Q and C matches R.
  • SSS, SAS, ASA, AAS and RHS are valid congruence criteria.
  • AAA and SSA do not guarantee congruence.
  • RHS applies only to right triangles.
  • Corresponding parts of congruent triangles are equal (CPCT).
  • Angles opposite equal sides of a triangle are equal.

12. Exam-pattern Questions with Detailed Answers

Q1Easy

Two circles are congruent if they have equal:

  1. centres
  2. radii
  3. chords
  4. positions
Show answer

A circle's size depends only on its radius.

Answer: (B) radii

Q2Easy

If ΔABC ≅ ΔXYZ, which side equals BC?

Show answer

B ↔ Y and C ↔ Z, so BC = YZ.

Answer: YZ

Q3Easy

Which criterion is used when all three sides of two triangles are equal?

Show answer

Three sides → SSS.

Answer: SSS

Q4Medium

In ΔPQR and ΔDEF, ∠P = ∠D, ∠Q = ∠E and PQ = DE. Are they congruent? State the criterion.

Show answer

PQ is between ∠P and ∠Q; DE is between ∠D and ∠E. Two angles and the included side → ASA.

Answer: Yes, by ASA (ΔPQR ≅ ΔDEF)

Q5Medium

Two triangles have angles 50°, 60°, 70° each. Must they be congruent?

  1. Yes, by AAA
  2. No, they may differ in size
  3. Yes, by ASA
  4. Only if right-angled
Show answer

Equal angles give the same shape but not necessarily the same size. AAA is not a congruence criterion.

Answer: (B)

Q6Medium

Lines AB and CD bisect each other at O. Prove that AC = BD.

Show answer

In ΔAOC and ΔBOD: OA = OB and OC = OD (bisect each other); ∠AOC = ∠BOD (vertically opposite). So ΔAOC ≅ ΔBOD by SAS, and AC = BD (CPCT).

Answer: Proved by SAS and CPCT

Q7Medium

In right triangles ABC and DEF (right-angled at B and E), AC = DF = 10 cm and BC = EF = 6 cm. Find AB and DE.

Show answer

By RHS the triangles are congruent, so AB = DE. Using the right-angle relation (6, 8, 10), AB = DE = 8 cm.

Answer: 8 cm each

Q8Medium

ΔABC ≅ ΔPQR with ∠A = 40° and ∠Q = 75°. Find ∠R and ∠C.

Show answer

∠P = ∠A = 40°, ∠B = ∠Q = 75°. ∠C = ∠R = 180° − 115° = 65°.

Answer: 65° each

Q9Hard

P is a point equidistant from the ends A and B of a segment AB, and M is the midpoint of AB. Show that PM is perpendicular to AB.

Show answer

ΔPAM ≅ ΔPBM by SSS (PA = PB, AM = BM, PM common). So ∠PMA = ∠PMB. They form a linear pair (sum 180°), so each is 90°.

Answer: ∠PMA = ∠PMB = 90°

Q10Hard

Explain with an example why SSA does not guarantee congruence.

Show answer

Take AB = 5 cm, ∠A = 30° and BC = 3 cm. Draw ∠A on a base line, mark B on the slanting arm, and draw an arc of radius 3 cm from B. The arc can cut the base line at two different points C₁ and C₂, giving two different triangles with the same SSA data.

Answer: Two different triangles can share the same SSA data

Q11Hard

In quadrilateral ABCD, AB = CD and AD = CB. Prove that ∠B = ∠D.

Show answer

Draw diagonal AC. In ΔABC and ΔCDA: AB = CD, BC = DA, AC common. So ΔABC ≅ ΔCDA by SSS, hence ∠B = ∠D (CPCT).

Answer: Proved by SSS

Q12Hard

Two ladders of equal length lean against two walls from points on the ground at equal distance from the walls. Are the heights they reach equal? Why?

Show answer

Each ladder, wall and ground form a right triangle with equal hypotenuses (ladders) and equal sides (distances from the walls). By RHS the triangles are congruent, so the heights are equal (CPCT).

Answer: Yes, by RHS

13. Quick Revision Summary

Revise in 2 minutes
  • Congruent = same shape and same size; written ≅.
  • Write congruences in matching order; corresponding parts are equal (CPCT).
  • Valid tests: SSS, SAS (included angle), ASA/AAS, RHS (right triangles).
  • Invalid tests: AAA, SSA.
  • Uses: proving isosceles base angles equal, perpendicular bisectors, distances across obstacles.