1. Chapter at a Glance
This chapter covers the arithmetic, mensuration, statistics and probability that form the backbone of CDS Elementary Mathematics (60–70 of 100 questions), the whole of AFCAT Numerical Ability (15–20 questions) and about 20–25 questions of NDA Paper I (statistics and probability). The level is Class X for CDS and AFCAT, but questions are time-pressed, so shortcuts and mental calculation matter as much as concepts. Every section below gives the concept, the shortcut and a worked example.
- Memorise squares up to 30, cubes up to 15, and the percentage values of fractions from 1/2 to 1/20 (1/8 = 12.5%, 1/6 = 16.67%, 1/12 = 8.33%).
- Learn each formula with one example; then solve 20 mixed questions daily under a timer.
- In CDS each question carries 1 mark and a wrong answer costs 0.33; in AFCAT +3 and −1. Leave a question only if you cannot eliminate any option.
2. Number System, HCF and LCM
- Natural numbers 1, 2, 3...; whole numbers 0, 1, 2...; integers include negatives; rational numbers p/q (q ≠ 0) have terminating or repeating decimals; irrational numbers (√2, π) do not.
- 2 is the only even prime. There are 25 primes below 100.
- Divisibility: by 3 or 9 if the digit sum is divisible by 3 or 9; by 4 if the last two digits form a multiple of 4; by 8 if the last three digits do; by 11 if (sum of odd-place digits − sum of even-place digits) is 0 or a multiple of 11.
- HCF × LCM = product of two numbers. HCF of fractions = HCF of numerators / LCM of denominators; LCM of fractions = LCM of numerators / HCF of denominators.
- Number of factors of N = p^a q^b r^c is (a + 1)(b + 1)(c + 1). Example: 72 = 2³ × 3² has 4 × 3 = 12 factors.
- Unit digit of powers: digits 2, 3, 7, 8 repeat in cycles of 4; 4 and 9 in cycles of 2; 0, 1, 5, 6 never change.
- Converting a recurring decimal: 0.ababab... = ab/99; 0.4777... = (47 − 4)/90 = 43/90.
3. Percentage, Profit and Loss, Discount
- x% of y = y% of x (8% of 50 = 50% of 8 = 4).
- If a value increases by a% and then by b%, the net change is a + b + ab/100 (use negative signs for decreases). A 10% rise followed by a 10% fall gives −1%.
- If the price rises by r%, consumption must fall by r/(100 + r) × 100% to keep expenditure unchanged (a 25% rise needs a 20% cut).
- Profit% = (Profit/CP) × 100; SP = CP × (100 + P%)/100. Discount is always on the marked price: SP = MP × (100 − D%)/100.
- Successive discounts of a% and b% equal a single discount of a + b − ab/100.
- If two articles are sold at the same price, one at x% profit and the other at x% loss, there is always a loss of x²/100 %.
- False weight: a dealer who uses 900 g for 1 kg and sells at cost gains 100/900 = 11.11%.
4. Simple and Compound Interest
- SI = PRT/100. Amount A = P + SI.
- Compound amount A = P(1 + R/100)ᵀ; half-yearly compounding: rate R/2, time 2T.
- Difference between CI and SI: for 2 years = P(R/100)²; for 3 years = P(R/100)²(3 + R/100).
- A sum doubles at SI in T years ⇒ R = 100/T. At CI, if a sum doubles in n years, it becomes 4 times in 2n years and 8 times in 3n years.
- Rule of 72: at CI of R%, money roughly doubles in 72/R years.
5. Ratio, Proportion, Partnership, Mixtures
- If a : b = c : d, then ad = bc. Mean proportional of a and b = √(ab); third proportional = b²/a.
- Partnership: profit is shared in the ratio of (capital × time).
- Alligation: when two items costing c₁ (cheaper) and c₂ (dearer) are mixed to get mean price m, quantity ratio = (c₂ − m) : (m − c₁).
- Repeated replacement: if x litres are removed from a vessel of V litres of pure liquid and replaced by water n times, pure liquid left = V(1 − x/V)ⁿ.
6. Averages and Ages
- Average = sum/number. Average of n consecutive numbers = middle term = (first + last)/2.
- If a new item raises the average of n items by d, the new item = old average + (n + 1)d.
- Average speed for equal distances at speeds x and y = 2xy/(x + y) (not the simple average).
- Age problems: write present ages as variables, translate each sentence into an equation; check the answer against all statements.
7. Time and Work, Pipes and Cisterns
- If A does a job in a days and B in b days, together they take ab/(a + b) days.
- LCM method: take total work = LCM of the days; find each person's per-day work; add or subtract efficiencies.
- M₁D₁H₁/W₁ = M₂D₂H₂/W₂ (men, days, hours, work).
- Pipes: filling pipes are positive, emptying pipes negative. A fills in 10 h, B empties in 15 h ⇒ net = 1/10 − 1/15 = 1/30, i.e. 30 hours.
8. Time, Speed and Distance
- Distance = speed × time. 1 km/h = 5/18 m/s; 1 m/s = 18/5 km/h.
- Relative speed: opposite directions add, same direction subtract.
- A train crossing a pole covers its own length; crossing a platform or another train covers the sum of the lengths.
- Boats: downstream speed = u + v, upstream = u − v; boat speed u = (D + U)/2, stream v = (D − U)/2.
- If a person travels at 3/4 of the usual speed and is late by t minutes, the usual time = 3t (generally, usual time = t × new speed/(usual speed − new speed)).
9. Mensuration
| Figure | Area / surface | Perimeter / volume |
|---|---|---|
| Triangle | ½ × base × height; Heron: √[s(s − a)(s − b)(s − c)] | a + b + c |
| Equilateral triangle (side a) | (√3/4)a² | Height (√3/2)a |
| Circle | πr²; sector (θ/360)πr² | 2πr; arc (θ/360)2πr |
| Rhombus | ½ d₁d₂ | side = ½√(d₁² + d₂²) |
| Trapezium | ½ (sum of parallel sides) × height | — |
| Cube (edge a) | TSA 6a² | V = a³; diagonal a√3 |
| Cuboid | 2(lb + bh + hl) | V = lbh; diagonal √(l² + b² + h²) |
| Cylinder | CSA 2πrh; TSA 2πr(r + h) | V = πr²h |
| Cone | CSA πrl (l = √(r² + h²)); TSA πr(l + r) | V = ⅓πr²h |
| Sphere / hemisphere | 4πr² / CSA 2πr², TSA 3πr² | ⁴⁄₃πr³ / ⅔πr³ |
If every length is multiplied by k, area becomes k² times and volume k³ times. Doubling the radius of a sphere multiplies its volume by 8. If the radius of a cylinder is doubled and height halved, its volume doubles.
10. Elementary Geometry (CDS)
- Sum of interior angles of an n-gon = (n − 2) × 180°; each exterior angle of a regular n-gon = 360°/n.
- Angle in a semicircle is 90°; angles in the same segment are equal; opposite angles of a cyclic quadrilateral sum to 180°.
- Tangent ⊥ radius at the point of contact; tangents from an external point are equal.
- Pythagorean triplets: (3, 4, 5), (5, 12, 13), (8, 15, 17), (7, 24, 25).
- Similar triangles: ratio of areas = square of the ratio of corresponding sides.
- In a triangle, the centroid divides each median 2 : 1; the circumcentre of a right triangle is the midpoint of the hypotenuse.
11. Statistics
- Mean x̄ = Σx/n (grouped: Σfx/Σf). Median = middle value of ordered data; mode = most frequent value.
- Empirical relation: Mode = 3 Median − 2 Mean.
- Variance σ² = Σ(x − x̄)²/n = Σx²/n − x̄²; standard deviation σ = √variance.
- Mean and SD of first n natural numbers: (n + 1)/2 and √[(n² − 1)/12].
- Effect of change: adding a constant to every observation changes the mean but not the variance or SD; multiplying by k multiplies the mean and SD by k and the variance by k².
- Coefficient of variation = (σ/x̄) × 100 — the series with the smaller CV is more consistent.
- Graphs: histogram (continuous classes), bar chart (discrete), ogive (cumulative frequency, used to find median), pie chart (each sector = value/total × 360°).
12. Probability
- P(E) = favourable outcomes / total outcomes; 0 ≤ P(E) ≤ 1; P(E′) = 1 − P(E).
- P(A ∪ B) = P(A) + P(B) − P(A ∩ B). Mutually exclusive: P(A ∩ B) = 0. Independent: P(A ∩ B) = P(A)P(B).
- Conditional probability P(A|B) = P(A ∩ B)/P(B).
- Two dice: 36 outcomes; most likely sum is 7 (6 ways). A deck has 52 cards: 4 suits × 13, 12 face cards, 4 aces.
- Binomial distribution: P(X = r) = ⁿCᵣ pʳ qⁿ⁻ʳ; mean np, variance npq.
- Odds in favour of E = P(E) : P(E′).
13. Data Interpretation and Quick Approximation
CDS Elementary Mathematics and the AFCAT Numerical Ability section regularly give a small table, bar chart or pie chart and ask three or four questions on it. These questions use only percentages, ratios and averages, but they reward a calm method. Read the title, the units (thousands, lakhs, crores) and the base year before touching any number.
- Percentage change = (New − Old)/Old × 100. The base is always the earlier or reference value.
- Percentage share of an item = item/total × 100. In a pie chart, an item's angle = share% × 3.6°.
- Average annual growth (simple) = total % growth ÷ number of years. Compound growth needs (final/initial)^(1/n) − 1.
- Ratio of two items can be read directly from the chart without finding the totals.
Worked table. The number of candidates (in thousands) who appeared for a defence entrance test in four years is: 2022 — 400, 2023 — 450, 2024 — 540, 2025 — 600.
| Question type | Working | Result |
|---|---|---|
| % increase from 2023 to 2024 | (540 − 450)/450 × 100 | 20% |
| % increase from 2022 to 2025 | (600 − 400)/400 × 100 | 50% |
| Average per year | (400 + 450 + 540 + 600)/4 | 497.5 thousand |
| Year with the highest growth over its previous year | 2023: 12.5%, 2024: 20%, 2025: 11.1% | 2024 |
| Ratio of 2022 to 2025 | 400 : 600 | 2 : 3 |
- The largest absolute increase is not always the largest percentage increase. From 540 to 600 is +60 (11.1%), while from 450 to 540 is +90 (20%).
- In a pie chart, a sector of 72° is 72/360 = 20% of the total, not 72%.
- If two charts use different totals, compare actual values, not percentages.
Approximation. In a timed paper, round numbers sensibly before calculating and then pick the nearest option. For example, 19.98% of 501 ≈ 20% of 500 = 100. Also, 4,987 ÷ 49.6 ≈ 5,000 ÷ 50 = 100, and √1,230 ≈ 35 because 35² = 1,225. Round one number up and the other down when multiplying so that the errors cancel. Approximation is safe only when the options are spread far apart; if two options are close, calculate exactly.
1/2 = 50%, 1/3 = 33.33%, 1/4 = 25%, 1/5 = 20%, 1/6 = 16.67%, 1/7 ≈ 14.28%, 1/8 = 12.5%, 1/9 ≈ 11.11%, 1/11 ≈ 9.09%, 1/12 = 8.33%, 1/15 = 6.67%, 1/16 = 6.25%. Learning these lets you turn 540/450 = 6/5 into a 20% increase at a glance.
14. Master Formula Table
| Topic | Formula | Quick example |
|---|---|---|
| HCF–LCM | HCF × LCM = a × b | HCF 4, LCM 48, a = 12 ⇒ b = 16 |
| Number of factors | (a + 1)(b + 1)(c + 1) | 72 → 12 factors |
| Successive change | a + b + ab/100 | +20%, −20% ⇒ −4% |
| Discount | SP = MP(100 − D)/100 | MP 800, 15% ⇒ 680 |
| Same SP, x% gain and loss | Loss = x²/100 % | 10% ⇒ 1% loss |
| Simple interest | PRT/100 | Doubles in T ⇒ R = 100/T |
| Compound interest | P(1 + R/100)ᵀ | CI − SI (2 yr) = P(R/100)² |
| Alligation | (c₂ − m) : (m − c₁) | 20, 30 → 27 ⇒ 3 : 7 |
| Work together | ab/(a + b) | 10, 15 days ⇒ 6 days |
| Average speed | 2xy/(x + y) | 60, 40 ⇒ 48 km/h |
| Units | km/h × 5/18 = m/s | 72 km/h = 20 m/s |
| Boats | u = (D + U)/2; v = (D − U)/2 | 15, 9 ⇒ 12 and 3 |
| Cone | V = ⅓πr²h; l = √(r² + h²) | r 3, h 4 ⇒ l 5 |
| Sphere | V = ⁴⁄₃πr³; S = 4πr² | r doubles ⇒ V × 8 |
| Mode | 3 Median − 2 Mean | Moderately skewed data |
| Variance | Σx²/n − x̄² | Unchanged by adding a constant |
| Probability | P(A ∪ B) = P(A) + P(B) − P(A ∩ B) | Independent: multiply |
| Binomial distribution | Mean np, variance npq | n = 10, p = 0.5 ⇒ mean 5 |
15. Master Summary Table
| Topic | CDS Qs | AFCAT Qs | NDA Qs | Most common trap |
|---|---|---|---|---|
| Number system, HCF-LCM | 8–12 | 2–3 | — | Unit-digit cycles |
| Percentage, profit-loss | 6–8 | 3–4 | — | Base of the percentage |
| Interest | 3–5 | 1–2 | — | Half-yearly conversion |
| Ratio, mixtures, average | 6–8 | 3–4 | — | Average speed |
| Time-work, speed-distance | 6–8 | 3–4 | — | Unit conversion |
| Mensuration | 8–10 | 2–3 | — | Curved vs total surface |
| Geometry | 10–12 | — | — | Cyclic quadrilateral angles |
| Statistics | 4–6 | 1 | 10–12 | Effect of scaling on variance |
| Probability | — | — | 8–10 | Exclusive vs independent |
16. Mind Map
- Divisibility
- HCF, LCM
- Unit digit, factors
- Percentage
- Profit, discount
- SI, CI
- Ratio, mixtures
- Time-work, pipes
- Speed, trains, boats
- 2D areas
- 3D volumes
- Circle, triangle theorems
- Mean, median, mode
- Variance, SD
- Probability
17. Tips and Tricks
- Square of a number ending in 5: 65² → 6 × 7 = 42, append 25 → 4225.
- Multiply by 25: divide by 4 and multiply by 100 (36 × 25 = 900).
- Use fraction equivalents: 37.5% = 3/8, 62.5% = 5/8, 87.5% = 7/8, 33.33% = 1/3.
- Back-solve with options in age, mixture and number problems — start with the middle option.
- For "percentage more/less" reversals use r/(100 ± r) × 100.
- Draw a quick diagram for every geometry and train question; label lengths and angles.
- In probability, count the complement when "at least one" appears: P(at least one) = 1 − P(none).
18. Important One-Liners
- 1 is neither prime nor composite; 2 is the smallest and only even prime.
- The product of two numbers equals the product of their HCF and LCM.
- A number is divisible by 6 if it is divisible by both 2 and 3.
- Discount is always calculated on the marked price, profit on the cost price.
- Simple interest is the same every year; compound interest grows every year.
- 1 km/h = 5/18 m/s.
- Relative speed is the sum of speeds for opposite directions.
- Average speed for equal distances is the harmonic mean of the speeds.
- The volume of a cone is one-third that of a cylinder with the same base and height.
- The angle in a semicircle is a right angle.
- Each interior angle of a regular hexagon is 120°.
- The median is not affected by extreme values; the mean is.
- Adding a constant to all observations does not change the standard deviation.
- Probability of an impossible event is 0 and of a sure event is 1.
- For two dice, the probability of getting a sum of 7 is 1/6.
- Mean of a binomial distribution is np.
19. PYQ-Based Questions with Detailed Answers
What is the unit digit of 7¹⁰⁵?
- 1
- 3
- 7
- 9
Answer and explanation
Unit digits of powers of 7 repeat as 7, 9, 3, 1 (cycle of 4). 105 = 4 × 26 + 1, so the unit digit is the first in the cycle, 7.
Answer: (C) 7
The HCF and LCM of two numbers are 12 and 144. If one number is 36, the other is:
- 24
- 48
- 60
- 72
Answer and explanation
Other number = (12 × 144)/36 = 48. Check: HCF(36, 48) = 12 and LCM = 144 ✓. 72 fails because HCF(36, 72) = 36.
Answer: (B) 48
The price of an article is increased by 25%. By what percentage must a family reduce consumption to keep expenditure unchanged?
- 20%
- 25%
- 15%
- 30%
Answer and explanation
Required cut = r/(100 + r) × 100 = 25/125 × 100 = 20%. Cutting 25% would reduce expenditure because the base for the cut is the new, higher price.
Answer: (A) 20%
A shopkeeper marks goods 40% above cost and allows a 25% discount. His profit or loss percentage is:
- 5% profit
- 5% loss
- 15% profit
- 10% profit
Answer and explanation
Take CP = 100. MP = 140; SP = 140 × 0.75 = 105. Profit = 5%. Formula check: 40 − 25 − (40 × 25)/100 = 40 − 25 − 10 = 5%.
Answer: (A) 5% profit
The difference between compound and simple interest on a sum for 2 years at 10% per annum is ₹50. The sum is:
- ₹4000
- ₹5000
- ₹2500
- ₹6000
Answer and explanation
CI − SI (2 years) = P(R/100)² ⇒ 50 = P × 0.01 ⇒ P = ₹5000.
Answer: (B) ₹5000
A train 240 m long passes a pole in 12 seconds. How long will it take to cross a platform 360 m long?
- 18 s
- 24 s
- 30 s
- 36 s
Answer and explanation
Speed = 240/12 = 20 m/s. Crossing the platform needs 240 + 360 = 600 m, so time = 600/20 = 30 s. 18 s uses only the platform length.
Answer: (C) 30 s
A and B can do a work in 12 days, B and C in 15 days, and C and A in 20 days. In how many days can A, B and C together finish it?
- 8
- 10
- 12
- 15
Answer and explanation
Total work = LCM(12, 15, 20) = 60 units. Per day: A + B = 5, B + C = 4, C + A = 3. Adding: 2(A + B + C) = 12 ⇒ A + B + C = 6 units/day. Time = 60/6 = 10 days.
Answer: (B) 10
The radius of a sphere is increased by 50%. Its volume increases by:
- 50%
- 125%
- 237.5%
- 337.5%
Answer and explanation
New volume factor = (1.5)³ = 3.375, so the increase is 3.375 − 1 = 2.375 = 237.5%. 125% is the increase in surface area (1.5² = 2.25).
Answer: (C) 237.5%
In a cyclic quadrilateral ABCD, ∠A = 70°. What is ∠C?
- 70°
- 90°
- 110°
- 140°
Answer and explanation
Opposite angles of a cyclic quadrilateral are supplementary: ∠C = 180° − 70° = 110°.
Answer: (C) 110°
The mean of 5 observations is 10 and their variance is 4. If each observation is multiplied by 3, the new variance is:
- 4
- 12
- 36
- 108
Answer and explanation
Multiplying every observation by k multiplies the variance by k². New variance = 9 × 4 = 36. The mean becomes 30 and the SD becomes 3 × 2 = 6.
Answer: (C) 36
Two dice are thrown. What is the probability that the sum is 8?
- 1/6
- 5/36
- 1/9
- 7/36
Answer and explanation
Favourable pairs: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) — 5 outcomes out of 36. Probability = 5/36. 1/6 is the probability of a sum of 7.
Answer: (B) 5/36
A coin is tossed 4 times. What is the probability of getting at least one head?
- 1/16
- 1/2
- 15/16
- 3/4
Answer and explanation
P(no head) = (1/2)⁴ = 1/16, so P(at least one head) = 1 − 1/16 = 15/16. Counting the complement is far faster than adding cases.
Answer: (C) 15/16
In what ratio must rice at ₹32/kg be mixed with rice at ₹42/kg so that the mixture, sold at ₹44/kg, gives a 10% profit?
- 1 : 4
- 4 : 1
- 2 : 3
- 1 : 2
Answer and explanation
First find the cost price of the mixture: a 10% profit at ₹44 means CP = 44/1.1 = ₹40/kg. Alligation gives cheaper : dearer = (dearer − mean) : (mean − cheaper) = (42 − 40) : (40 − 32) = 2 : 8 = 1 : 4. Check: (1 × 32 + 4 × 42)/5 = 200/5 = ₹40 ✓. Taking ₹44 itself as the mean (without removing the profit) is the usual mistake; 4 : 1 reverses the ratio.
Answer: (A) 1 : 4
In a pie chart showing the expenditure of a unit, the share of rations is represented by a sector of 108°. If the total expenditure is ₹20 lakh, how much is spent on rations?
- ₹6 lakh
- ₹10.8 lakh
- ₹5.4 lakh
- ₹3.6 lakh
Answer and explanation
A full circle of 360° stands for 100%. 108° is 108/360 = 30% of the total, and 30% of ₹20 lakh = ₹6 lakh. Taking 108 as a percentage, or dividing by 3.6 twice, gives the wrong options.
Answer: (A) ₹6 lakh
The approximate value of 49.89% of 801.2 + 24.97% of 399.6 is:
- 500
- 450
- 550
- 600
Answer and explanation
Round sensibly: 50% of 800 = 400 and 25% of 400 = 100, giving about 500. The exact value is about 499.6, so 500 is the closest option.
Answer: (A) 500
A battalion's fuel use was 400, 450, 540 and 600 kilolitres in four successive years. In which year was the percentage increase over the previous year the highest?
- Third year
- Second year
- Fourth year
- The increase was equal every year
Answer and explanation
Increases: 450/400 → 12.5%, 540/450 → 20%, 600/540 → about 11.1%. The third year shows the highest percentage rise. Note that the fourth year has a larger value but a smaller percentage rise, because the base (540) is bigger — always divide by the earlier value.
Answer: (A) Third year
20. Quick Revision Summary
- Numbers: divisibility rules, HCF × LCM = product, factors (a + 1)(b + 1)..., unit-digit cycles.
- Percentage: a + b + ab/100; consumption cut r/(100 + r); discount on MP, profit on CP.
- Interest: SI = PRT/100; CI = P(1 + R/100)ᵀ; CI − SI = P(R/100)² for 2 years.
- Ratio and mixtures: alligation (c₂ − m) : (m − c₁); partnership by capital × time.
- Work and speed: ab/(a + b); 5/18; relative speed; average speed 2xy/(x + y).
- Mensuration: areas and volumes table; scaling k², k³.
- Geometry: angle sums, circle theorems, Pythagorean triplets, similar-triangle area ratio.
- Statistics: mean, median, mode, variance; effect of adding and multiplying constants.
- Probability: complement rule, addition rule, independent events, binomial mean np.