Class 9 Science · Chapter 5

Exploring Mixtures and their Separation

Types of mixtures, solutions and concentration, suspensions and colloids (Tyndall effect), crystallisation, distillation, centrifugation, chromatography and separating immiscible liquids.

NCERT ExplorationCBSE Class 9 12 min read

1. Chapter at a Glance

Almost everything around us is a mixture — air, sea water, milk, soil, crude oil, ink, even the blood in our veins. To use the components of a mixture, we must often separate them: salt from sea water, petrol from crude oil, pure water from impure water, dyes from ink. This chapter classifies mixtures (solutions, suspensions and colloids), shows how to express the concentration of a solution, and explains the important separation techniques used in laboratories, homes and industries — including India’s traditional deg–bhapka distillation of attar.

What you will learn
  • Pure substances vs mixtures; homogeneous vs heterogeneous mixtures.
  • Solutions, suspensions and colloids; the Tyndall effect.
  • Concentration of a solution — mass % and mass by volume %.
  • Crystallisation, simple and fractional distillation, sublimation, centrifugation, chromatography.
  • Separating immiscible liquids; water treatment by coagulation.

2. How Can We Classify Mixtures?

A pure substance has a single kind of particle and fixed properties (e.g. pure water boils at 100 °C at 1 atm). A mixture contains two or more substances in any ratio, each keeping its properties.

  • Homogeneous mixture — uniform composition throughout; one phase (salt solution, air, brass).
  • Heterogeneous mixture — non-uniform; components can be distinguished (sand in water, oil and water, soil).

3. Solutions, Suspensions and Colloids

Salt in water as a solution with no settling, chalk in water as a suspension that settles, diluted milk as a colloid that does not settle, and a torch beam showing no visible path in the solution but a visible path in the colloid
Solution, suspension and colloid compared; the colloid shows the Tyndall effect.
PropertySolutionColloidSuspension
Particle sizeSmallest (< 1 nm)Intermediate (1–1000 nm)Largest (> 1000 nm)
AppearanceClear, transparentAppears uniform; may be translucentCloudy, opaque
NatureHomogeneousHeterogeneous (looks homogeneous)Heterogeneous
Settling on standingNoNo (stable)Yes
FiltrationPasses throughPasses through filter paperCan be filtered
Tyndall effectNoYesMay scatter light
ExamplesSalt/sugar in water, air, sodaMilk, fog, smoke, jelly, shaving cream, bloodChalk in water, muddy water, sand in water

The Tyndall effect is the scattering of a beam of light by colloidal particles, making the path of light visible — like sunbeams in a dusty room or headlight beams in fog. A colloid has a dispersed phase (particles) spread in a dispersion medium. For example, in fog, water droplets (liquid) are dispersed in air (gas) — an aerosol; milk is an emulsion (liquid in liquid); jelly is a gel (liquid in solid).

4. Solutions and Their Concentration

A solution has a solute (smaller component, dissolved) and a solvent (larger component). A saturated solution cannot dissolve more solute at that temperature; the amount dissolved in 100 g of solvent is the solubility.

Mass percentage = (mass of solute ÷ mass of solution) × 100

Mass by volume percentage = (mass of solute in g ÷ volume of solution in mL) × 100

Worked examples
  1. 40 g of salt in 320 g of water: mass of solution = 360 g; concentration = 40/360 × 100 = 11.1%.
  2. A 5% (mass/volume) glucose solution: 5 g glucose in 100 mL of solution; 500 mL contains 25 g glucose.
  3. To make 200 g of a 10% sugar solution: sugar = 20 g, water = 180 g.

5. Crystallisation

Crystallisation obtains a pure solid in crystal form from its solution. It is better than simple evaporation because some solids decompose or char on strong heating, and soluble impurities stay behind in the solution.

  1. Prepare a saturated solution of impure copper sulphate in hot water.
  2. Filter the hot solution to remove insoluble impurities.
  3. Cool the filtrate slowly and leave it undisturbed.
  4. Collect the blue crystals (CuSO₄·5H₂O) and dry them on filter paper.
Preparing a hot saturated copper sulphate solution, filtering it, cooling the filtrate and collecting blue crystals
Crystallisation of copper sulphate in four steps.

Uses: purification of salt from sea water, alum (phitkari) from impure samples, sugar from cane juice.

6. Distillation

Simple distillation separates a liquid from a dissolved solid, or two miscible liquids whose boiling points differ by more than about 25 °C. The liquid is boiled; its vapour is cooled in a Liebig condenser (cold water enters at the lower end and leaves at the upper end) and collected as the distillate.

Distillation flask with copper sulphate solution on a heating mantle, thermometer, Liebig condenser with water in at the lower end and out at the upper end, and distilled water collected in a receiving flask
Simple distillation: vapour is condensed and collected as pure distilled water.

Fractional distillation separates miscible liquids with close boiling points using a fractionating column — for example, separating gases of air (nitrogen, oxygen, argon) after liquefying it, and separating crude petroleum into fractions. In a refinery tower, heated crude oil vapours rise and cool; heavier fractions condense lower (hotter) and lighter ones higher (cooler).

A petroleum refinery and a simplified fractional distillation column separating refinery gases, petrol, naphtha, kerosene, diesel and heavy residue
Fractional distillation of crude petroleum into useful fractions.
India’s traditional distillation — deg–bhapka

In Kannauj (Uttar Pradesh), attar has been made for centuries using copper stills. Flowers like rose are heated with water in a deg sealed with clay; fragrant vapour travels through a bamboo pipe (chonga) into a bhapka (receiver) kept in cool water, where it condenses into a base of sandalwood oil.

Copper deg with rose petals and water heated on a bhatti furnace, a bamboo chonga pipe carrying vapour to a bhapka receiver in cooling water with sandalwood oil
The traditional Indian deg–bhapka method of making attar.

7. Separating Components of Heterogeneous Mixtures

MethodPrincipleExample
SublimationOne component changes directly from solid to vapourCamphor, naphthalene, ammonium chloride, iodine from sand or salt
CentrifugationRapid spinning forces denser particles to the bottomCream from milk, blood tests, washing machine drier
ChromatographyComponents move at different speeds with a solventDyes in ink, pigments in leaves, drugs in blood
Separating funnelImmiscible liquids form layers by densityOil and water, kerosene and water
Magnetic separationMagnetic component attractedIron filings from sulphur

Sublimation

Heat a mixture of camphor and sand in a dish covered with an inverted funnel plugged with cotton. Camphor turns directly into vapour and deposits as solid crystals on the cool inner surface of the funnel; sand remains in the dish.

Camphor and sand heated in a dish under an inverted funnel with a cotton plug; camphor vapour rises and deposits as crystals on the cool funnel
Sublimation separates camphor from sand: solid → vapour → solid.
A laboratory centrifuge with closed lid, control panel, rotor with balanced sample tubes, and a tube before and after spinning showing supernatant and pellet
A centrifuge: rapid spinning separates suspended particles into a pellet.

Chromatography

Put a spot of ink on a pencil line drawn about 3 cm from the bottom of a strip of filter paper. Dip the strip in a solvent (water or alcohol) so that the solvent level is below the spot. As the solvent rises, the dyes in the ink move with it — the more soluble dye travels farther — and separate into coloured bands. The word comes from the Greek kroma, colour.

A chromatography paper with an ink spot on a pencil baseline above the solvent, and after separation showing blue, green, yellow and red bands below the solvent front
Paper chromatography separates the dyes in ink.

Separating immiscible liquids

Pour the mixture into a separating funnel and let it stand. The denser liquid (water) settles below; the lighter one (oil) floats above. Open the stopcock and drain the lower layer, closing it as soon as the boundary reaches the tap.

Separating funnel with oil as the upper layer and water as the lower layer, and the water drained through the stopcock into a beaker
Separating immiscible liquids: the denser liquid is drained from below.

8. Water Treatment — Coagulation

River water contains fine clay particles that do not settle easily. In water treatment plants, alum (potash alum) is added as a coagulant; it makes fine particles stick together into larger flocs (flocculation), which settle down (sedimentation). The clearer water is then filtered and disinfected (chlorination) before supply.

Four beakers: cloudy water, alum added, flocs forming during gentle mixing, and flocs settled at the bottom with clearer water above
Coagulation in water treatment: alum gathers fine particles into flocs that settle.
Raw watersettling + Alumcoagulation Filtration Chlorination Supply Stages in a water purification plant
Simplified stages of water treatment.

9. Master Table: Formulas and Methods

ItemFormula / principle
Mass %solute mass ÷ solution mass × 100
Mass by volume %solute mass (g) ÷ solution volume (mL) × 100
Simple distillationBoiling point difference > ~25 °C
Fractional distillationClose boiling points; fractionating column
SublimationSolid → vapour directly
CentrifugationDensity difference under rapid spinning
ChromatographyDifferent solubility and movement with solvent
Tyndall effectScattering of light by colloidal particles

10. Master Summary Table

MixtureBest method
Salt from sea water (pure crystals)Crystallisation
Pure water from salt waterSimple distillation
Petrol, diesel from crude oilFractional distillation
Camphor from sandSublimation
Cream from milkCentrifugation
Dyes in inkChromatography
Oil from waterSeparating funnel
Clay from river waterCoagulation + sedimentation + filtration

11. Mind Map

Mixtures and Separation
Types
  • Homogeneous, heterogeneous
  • Solution, colloid, suspension
Concentration
  • Mass %
  • Mass by volume %
Methods
  • Crystallisation, distillation
  • Sublimation, centrifuge, chromatography
Applications
  • Refinery, attar
  • Water treatment

12. Tips and Tricks

Smart ideas
  • Particle size order: Solution < Colloid < Suspension (“S-C-S, small to big”).
  • Sublimable solids: “CANI” — Camphor, Ammonium chloride, Naphthalene, Iodine.
  • Condenser rule: water in at the bottom, out at the top — keeps the jacket full.
  • In mass % problems, always add solute + solvent for the solution mass.
Common mistakes
  • Using solvent mass instead of solution mass in the formula.
  • Saying colloids settle on standing — they do not.
  • Placing the chromatography spot below the solvent level — the dye would dissolve into the solvent.

13. Important One-liners

  • A solution is a homogeneous mixture.
  • Colloids show the Tyndall effect; true solutions do not.
  • Particles of a suspension settle on standing.
  • Milk is an emulsion; fog is an aerosol.
  • Crystallisation gives purer crystals than evaporation.
  • Crude oil is separated by fractional distillation.
  • Camphor and naphthalene sublime.
  • Cream is separated from milk by centrifugation.
  • Chromatography separates dyes in ink.
  • Alum helps fine particles in water form flocs that settle.

14. Exam-pattern Questions with Detailed Answers

Q1Easy

Which of the following shows the Tyndall effect?

  1. Salt solution
  2. Sugar solution
  3. Milk
  4. Copper sulphate solution
Show answer

Milk is a colloid; its particles scatter light. The others are true solutions.

Answer: (C) Milk

Q2Easy

Name the method to separate cream from milk.

Show answer

Centrifugation — lighter cream collects at the top on rapid spinning.

Answer: Centrifugation

Q3Easy

Classify as homogeneous or heterogeneous: soda water, wood, air, soil.

Show answer

Homogeneous: soda water, air. Heterogeneous: wood, soil.

Answer: Soda water, air — homogeneous; wood, soil — heterogeneous

Q4Medium

A solution contains 40 g of common salt in 320 g of water. Calculate the concentration in mass percentage.

Show answer

Mass of solution = 360 g. Concentration = 40/360 × 100 = 11.1%.

Answer: 11.1%

Q5Medium

Assertion (A): Crystallisation is better than evaporation for obtaining pure copper sulphate. Reason (R): Some solids decompose on strong heating and soluble impurities remain in the solution during crystallisation.

  1. Both true; R explains A
  2. Both true; R does not explain A
  3. A true, R false
  4. A false, R true
Show answer

Both correct, and R gives the exact reasons why crystallisation yields purer crystals.

Answer: (A)

Q6Medium

How will you separate a mixture of ammonium chloride and common salt?

Show answer

By sublimation. Heat the mixture in a dish covered with an inverted funnel. Ammonium chloride sublimes and deposits on the cool funnel; common salt remains in the dish.

Answer: Sublimation

Q7Medium

Why is cold water passed into the Liebig condenser from the lower end?

Show answer

Entering from the bottom fills the jacket completely with water, giving efficient cooling along its whole length, and the coldest water meets the vapour near the outlet so condensation is complete.

Answer: Keeps the jacket full for efficient cooling

Q8Medium

Give three differences between a colloid and a suspension.

Show answer

Colloid particles are smaller (1–1000 nm) and do not settle; suspension particles are larger and settle. Colloids pass through filter paper; suspensions can be filtered. Colloids are stable and look uniform; suspensions are unstable and cloudy.

Answer: Size, settling, filtration

Q9Hard

How are the gases of air separated? Name the method and explain briefly.

Show answer

Air is compressed and cooled to form liquid air, then allowed to warm slowly in a fractional distillation column. Gases boil off at their own boiling points (nitrogen −196 °C, argon −186 °C, oxygen −183 °C) and are collected separately at different heights.

Answer: Liquefaction followed by fractional distillation

Q10Hard

Case-based: A forensic team finds an ink spot on a letter and wants to check if it matches a suspect’s pen. (a) Which technique will they use? (b) Describe the procedure. (c) What result would show a match?

Show answer

(a) Chromatography. (b) Spot both inks on a pencil baseline on chromatography paper; dip the paper in a solvent kept below the baseline; let the solvent rise. (c) If both spots separate into the same coloured bands at the same heights, the inks match.

Answer: Chromatography; identical band patterns indicate a match

Q11Hard

Suggest a scheme to separate a mixture of sand, iron filings, common salt and camphor.

Show answer

(1) Remove iron filings with a magnet. (2) Heat the remainder: camphor sublimes and is collected on a cool funnel. (3) Add water to sand and salt; stir and filter — sand remains as residue. (4) Evaporate or crystallise the filtrate to get salt.

Answer: Magnet → sublimation → dissolve and filter → evaporate

Q12Hard

How much glucose is needed to prepare 250 mL of a 5% (mass by volume) glucose solution for a patient? Why must such solutions be prepared accurately?

Show answer

5 g per 100 mL → 250 mL needs 12.5 g glucose. Accuracy matters because too concentrated or too dilute solutions can harm body cells through osmosis and affect blood sugar.

Answer: 12.5 g; precise concentration protects cells

15. Quick Revision Summary

Revise in 2 minutes
  • Mixtures: homogeneous (solutions) and heterogeneous (suspensions); colloids lie between and show the Tyndall effect.
  • Concentration: mass % and mass by volume %.
  • Crystallisation for pure solids; simple distillation for liquid–solid or widely different liquids; fractional distillation for close boiling points (crude oil, air).
  • Sublimation (camphor), centrifugation (cream), chromatography (dyes), separating funnel (oil–water).
  • Water treatment uses alum (coagulation), sedimentation, filtration and chlorination; deg–bhapka is India’s traditional distillation.